Answer: (3x + 11y)^2
Demonstration:
The polynomial is a perfect square trinomial, because:
1) √ [9x^2] = 3x
2) √121y^2] = 11y
3) 66xy = 2 *(3x)(11y)
Then it is factored as a square binomial, being the factored expression:
[ 3x + 11y]^2
Now you can verify working backwar, i.e expanding the parenthesis.
Remember that the expansion of a square binomial is:
- square of the first term => (3x)^2 = 9x^2
- double product of first term times second term =>2 (3x)(11y) = 66xy
- square of the second term => (11y)^2 = 121y^2
=> [3x + 11y]^2 = 9x^2 + 66xy + 121y^2, which is the original polynomial.
The length of the other leg is 12 cm
Answer:
f(x) = |x|, f(x) = [x] + 6
Step-by-step explanation:
Almost all of these are absolute values equations, which means the y doesn't change if x is positive or negative. The first one is the parent form, which is the simplest equation of the absolute equation, so it's symmetric with respect to the y-axis. The second equation is translated 3 units to the left, and the third is translated 31 to the left. The forth is translated 6 up, so it's still symmetric with respect to the y-axis. The fifth is translated 61 units left, and the last one is simply a line, which isn't symmetric.
(a) Without solving the equation we can't determine whether its true or false.
(b) If x = 3
4x + 1 = 2x + 5
4(3) + 1 = 2(3) + 5
12 + 1 = 15 + 5
13 = 20
No, if x = 3, the equation will not be true.
(c) 4x + 1 = 2x + 5
4x - 2x = 5 - 1
2x = 4
x = 4/2
x = 2
This shows that x = 2 makes the equation true.
