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Bess [88]
3 years ago
9

How do you find 3w-6w+3w×7×7×6×5÷9+2

Mathematics
1 answer:
Viktor [21]3 years ago
3 0
Let's remember orders of operations as we go through the craze of this problem.
We need to multiply or divide from left to right.
3w-6w+3w×7×7×6×5÷9+2
3w-6w+21w×7×6×5÷9+2
3w-6w+147w×6×5÷9+2
3w-6w+882w×5÷9+2
3w-6w+4,410w÷9+2
3w-6w+490w+2
-3w+490w+2
487w+2
To check that we simplified the expression right, I like to put in 1 for w and test it in the original expression and then the simplified expression (not needed).
487+2=489
3-6+3×7×7×6×5÷9+2=489
So that expression equals 487w+2.
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Rashid can do a piece of work in 8 days, which Tipu can finish in 12 days. If they work at it on alternate days with Rashid begi
algol [13]

Answer:

The work will be finished in 10 days.

Step-by-step explanation:

Rashid can do a piece of work in 8 days

This means that each day he works, Rashid does \frac{1}{8} of the work.

Tipu can finish in 12 days.

This means that each day he works, Tipu does \frac{1}{12} of the work.

Each 2 days:

Each 2 days they work, the amount done is given by:

\frac{1}{8} + \frac{1}{12} = \frac{3 + 2}{24} = \frac{5}{24}

Each 2 days, 5/24 of the work is done:

The number of periods of 2 days that is needed to finish the work(100% = 1 completed), is given by:

d = \frac{1}{\frac{5}{24}} = \frac{24}{5} = 4.8

2*4.8 = 9.6

Rounding up

The work will be finished in 10 days.

3 0
2 years ago
Find an equation of the tangent line to the curve 2(x^2+y^2)2=25(x^2−y^2) (a lemniscate) at the point (3,1)
Sholpan [36]
\bf 2[x^2+y^2]^2=25(x^2-y^2)\qquad \qquad 
\begin{array}{lllll}
&x_1&y_1\\
%   (a,b)
&({{ 3}}\quad ,&{{ 1}})\quad 
\end{array}\\\\
-----------------------------\\\\
2\left[ x^4+2x^2y^2+y^4 \right]=25(x^2-y^2)\qquad thus
\\\\\\
2\left[ 4x^3+2\left[ 2xy^2+x^22y\frac{dy}{dx} \right]+4y^3\frac{dy}{dx} \right]=25\left[2x-2y\frac{dy}{dx}  \right]
\\\\\\
2\left[ 4x^3+2\left[ 2xy^2+x^22y\frac{dy}{dx} \right]+4y^3\frac{dy}{dx} \right]=50\left[x-y\frac{dy}{dx}  \right]
\\\\\\


\bf \left[ 4x^3+2\left[ 2xy^2+x^22y\frac{dy}{dx} \right]+4y^3\frac{dy}{dx} \right]=25\left[x-y\frac{dy}{dx}  \right]
\\\\\\
4x^3+4xy^2+4x^2y\frac{dy}{dx}+4y^3\frac{dy}{dx}+25y\frac{dy}{dx}=25x
\\\\\\
\cfrac{dy}{dx}[4x^2y+4y^3+25y]=25x-4x^3+4xy^2
\\\\\\
\cfrac{dy}{dx}=\cfrac{25x-4x^3+4xy^2}{4x^2y+4y^3+25y}\impliedby m=slope

notice... a derivative is just the function for the slope

now, you're given the point 3,1, namely x = 3 and y = 1

to find the "m" or slope, use that derivative, namely f'(3,1)=\cfrac{25x-4x^3+4xy^2}{4x^2y+4y^3+25y}

that'd give you a value for the slope

to get the tangent line at that point, simply plug in the provided values
in the point-slope form

\bf y-{{ y_1}}={{ m}}(x-{{ x_1}})\qquad
\begin{cases}
x_1=3\\
y_1=1\\
m=slope
\end{cases}\\ \qquad \uparrow\\
\textit{point-slope form}

and then you solve it for "y", I gather you don't have to, but that'd be the equation of the tangent line at 3,1

6 0
3 years ago
a hotel survey shows that nearly 30% of the guest staying at the hotel were there for personal reasons. the remainder of the gue
kondor19780726 [428]

Answer:70% is the rest

Step-by-step explanation:

5 0
3 years ago
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Answer: my but

Step-by-step explanation:

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2 years ago
Use synthetic division to find P (-10) for P(x)=2x^3+14x^2-58x
Savatey [412]
The polynomial remainder theorem states that the remainder upon dividing a polynomial p(x) by x-c is the same as the value of p(c), so to find p(-10) you need to find the remainder upon dividing

\dfrac{2x^3+14x^2-58x}{x+10}

You have

..... | 2 ...  14  ... -58
-10 |    ... -20  ... 60
--------------------------
..... | 2 ...  -6  ....  2

So the quotient and remainder upon dividing is

\dfrac{2x^3+14x^2-58x}{x+10}=2x-6+\dfrac2{x+10}

with a remainder of 2, which means p(-10)=2.
5 0
3 years ago
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