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Rasek [7]
3 years ago
9

What is the value of this expression when X=-1 and Y = 2? 44²7²

Mathematics
1 answer:
jeyben [28]3 years ago
6 0

For the example in the explanation the result is:

\boxed{E=-1}

<h2>Explanation:</h2>

Hello! remember to write complete questions in order to find good and exact answers. Here you haven't provided any expression so I'll help you writing an expression. Suppose your expression is:

E=XY^2+2Y+X

So in order to know the value of our expression E, we need to substitute both x and y in it, so:

E=XY^2+2Y+X \\ \\ E=(-1)(2)^2+2(2)-1 \\ \\ E=-4+4-1 \\ \\ \boxed{E=-1}

<h2>Learn more:</h2>

Distributive property: brainly.com/question/10794694

#LearnWithBrainly

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I'm having trouble on ixl here is what I have to do
Sophie [7]

Answer:

6(9r-7)

Step-by-step explanation:

54r–42

Both 54 and 43 can be divided by 6

54/6 =9  and 42/6 =7

6*9r - 6*7

Factor out the 6

6(9r-7)

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3 years ago
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Answer:

9) 28

10) 22

Step-by-step explanation:

collinear means on the same line

9 ) AB+BC=AC

    16+12=28

10) 13+9=22

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3 years ago
A city planner wants to build a road parallel to 2nd Ave . What is the slope of the new road?
ludmilkaskok [199]

Answer:

0

Step-by-step explanation:

By inspection or finding points, we see that 2nd ave is perfectly flat, or in other words, has slope of 0.

If line 1 is parallel to line 2, it means their slopes are the same.

So, the new road parallel to 2nd ave has a slope of \boxed{0}.

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2 years ago
Explain why the sum of the angle measures in any triangle is 180
MA_775_DIABLO [31]
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Describe the rotation of J
Serga [27]

Answer:

The coordinates of J' when rotating by 90° counterclockwise will be: J'(3, 1)

The coordinates of J' when rotating by 90° clockwise will be: J'(-3, -1)

Step-by-step explanation:

Square JKLM with vertices

  • J(1, -3)
  • K(5, 0)
  • L(8, -4)
  • M(4, -7)

We have to determine the answer for the image J' of the point (1, -3) when we rotate the point by 90° counterclockwise, we need to switch x and y, make y negative.

In other words, the rule to rotate a point by 90° counterclockwise.

P(x, y) → P'(-y, x)

As we are given that J(1, -3), so the coordinates of J' will be:

J(1, -3) → J'(3, 1)

Therefore, the coordinates of J' when rotating by 90° counterclockwise will be:  J'(3, 1).

When the point is rotated by 90° clockwise, we need to switch x and y, make x negative.

In other words, the rule to rotate a point by 90° clockwise.

P(x, y) → P'(y, -x)

As we are given that J(1, -3), so the coordinates of J' will be:

J(1, -3) → J'(-3, -1)

Therefore, the coordinates of J' when rotating by 90° clockwise will be:  J'(-3, -1)

3 0
2 years ago
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