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Mkey [24]
2 years ago
10

Find the point slope equation for the line that passes through the points (7,-21) (-4,23)

Mathematics
1 answer:
zheka24 [161]2 years ago
5 0

\bf (\stackrel{x_1}{7}~,~\stackrel{y_1}{-21})\qquad (\stackrel{x_2}{-4}~,~\stackrel{y_2}{23}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{23-(-21)}{-4-7}\implies \cfrac{23+21}{-11}\\\\\\ \cfrac{44}{-11}\implies -4 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-(-21)=-4(x-7)\implies y+21=-4(x-7)

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The distance between Taylor’s house and her school is 300,000 centimeters.
Sergio [31]

Answer:

30 km

Step-by-step explanation:

1 kilometer = 100 meters.

1 meter = 100 cm

therefore, 1 km = 10,000

and then, 300000 cm is 30 km

7 0
3 years ago
Can someone help me please I need the mode, median, range and the mean.?
Neko [114]

Answer:

First the mode.  Since 5 popped up the most, 5 is the mode.

Next is the median.  I crossed 1 dot from each side until it shows the last dot, and 5 was the last one.

After that the range.  9-2=7

Finally the worst, the mean... 2+2+3+3+3+4+5+5+5+5+5+6+6+6+8+9+9+9+9

=104/19=5.47

SO, Mode=5 Median=5 Range=7, and the mean is 5.47 (rounded nearest hundred)

7 0
3 years ago
Please help with this question
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5 0
3 years ago
In the figure, AB║CD and ∠EIA is congruent to ∠GJB Complete the following statements to prove that ∠IKL is congruent to ∠DLH.
Finger [1]

Here it is given that AB || CD

< EIA = <GJB

Now

∠EIA ≅ ∠IKC and ∠GJB is ≅ ∠ JLD (Corresponding angles)

∠EIA  ≅ ∠GJB then ∠IKC ≅ ∠ JLD (Substitution Property of Congruency)

∠IKL + ∠IKC 180° and ∠DLH +  ∠JLD =180° (Linear Pair Theorem)

So

m∠IKL + m∠IKC = 180°       ....(1)

But ∠IKC  ≅ ∠JLD

m∠IKC = m∠JLD (SUBTRACTION PROPERTY OF CONGRUENCY)

So we have

m∠IKL + m∠JLD = 180°

∠IKL and ∠JLD are supplementary angles.

But ∠DLH and ∠JLD are supplementary angles.

∠IKL ≅ ∠DLH (CONGRUENT SUPPLEMENTS THEOREM)

7 0
2 years ago
Read 2 more answers
Simplify the expression. -2/3c -9/5 + 14c + 3/10
Andrew [12]

Answer:

13 \frac{1}{3} c - 1 \frac{1}{2}

Step-by-step explanation:

We want to combine alike terms so

-2/3c+14c & -9/5+3/10

14c-2/3

\frac{14}{1} c -  \frac{2}{3} c

Multiply 14/1 by 3/3 to get the denominators the same

\frac{42}{3} c -  \frac{2}{3} c

Subtract

\frac{40}{3} c

simplify

13 \frac{1}{3} c

now

\frac{3}{10}  -  \frac{9}{5}

Multiply 9/5 by 2/2

\frac{3}{10}  -  \frac{ 18}{10}

Subtract

- \frac{15}{10}

Simplify

- 1 \frac{1}{2}

put both together

13 \frac{1}{3}c  - 1 \frac{1}{2}

Hope this helps! If you have any questions on how I got my answer feel free to ask. Stay safe!

5 0
2 years ago
Read 2 more answers
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