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Mathematics

1 answer:

GREYUIT [131]3 years ago

6 0

my number 5467832342

Step-by-step explanation:

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Varvara68 [4.7K]

Answer:25

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3 years ago

Which of the follow is a factor of 3x^3+18x^2+27x

blagie [28]

3x(x+3)^2 is your answer
start 3x^3+18x^2+27x
Pull out common factor of 3x
3x(x^2+6x+9)
Factor into 2 (x+3)s
then combine
3x(x+3)^2
Your factors are 3x, (x+3) and (x+3)

Hope this helps. If it did, make it brainliest

3 0

4 years ago

Read 2 more answers

Find the coordinates of the intersection of the diagonals of parallelogram HJKL with the given vertices: H(-1, 4), J(3, 3), K(3,

lakkis [162]

Answer:

(1, 1)

Step-by-step explanation:

Given vertices of the parallelogram:

H = (-1, 4)
J = (3, 3)
K = (3, -2)
L = (-1, -1)

Therefore the parallel sides are:

$\sf \overline{HJ} \parallel \overline{LK}\:\: \textsf{ and }\:\: \overline{LK} \parallel \overline{HL}$

Therefore, the diagonals of the parallelogram are:

$\sf \overline{LJ} \:\: \textsf{ and }\:\:\overline{HK}$

To find the coordinates of the intersection of the diagonals, either:

draw a diagram (see attached) and determine the point of intersection of the diagonals from the diagram, or
determine the midpoint of either diagonal (as the diagonals of a parallelogram bisect each other, i.e. divide into 2 equal parts).

Midpoint between two points

$\textsf{Midpoint}=\left(\dfrac{x_2+x_1}{2},\dfrac{y_2+y_1}{2}\right)\quad \textsf{where}\:(x_1,y_1)\:\textsf{and}\:(x_2,y_2)\:\textsf{are the endpoints}}\right)$

To find the midpoint of diagonal LJ, define the endpoints:

$(x_1,y_1)=L=(-1, -1)$
$(x_2,y_2)=J=(3,3)$

Substitute the defined endpoints into the formula and solve:

$\begin{aligned} \implies \textsf{Midpoint of LJ} & =\left(\dfrac{3-1}{2},\dfrac{3-1}{2}\right)\\ & =\left(\dfrac{2}{2},\dfrac{2}{2}\right)\\ & =\left(1,1\right) \end{aligned}$