. What happens if you don't pay your insurance premium for your car?

Ford motor co. has separate divisions for passenger cars, for large trucks, and for farm products. ford is an example of an orga

Tamiku [17]

<span>range of products, which effectively provides the public with a fundamental tool at this time, both to work and to have fun in a recreational activity. They can also offer the models of their vehicles a comfort for the whole family.</span>

4 0

3 years ago

Determine what some skills used in science are. name one science skill that you have used today

ivolga24 [154]

The basic science process skills include the following: observing, inferring, measuring, communicating, classifying and predicting.
When these skills are well developed in a scientist, such a scientist will be able to identify variables, formulate hypothesis, interpret data, conduct experiment and formulate models.<span />

8 0

3 years ago

Melanie owns a bakery and has just purchased new powerful mixing machines that will increase her daily output of baked goods. Th

maria [59]

Answer:

A

Explanation:

Here are the options :

A.physical capital.B.technology.C.human capital.D.financial capital.

Physical capital can be described as tangible, man-made objects used to produce goods. They include machinery, cars

3 0

2 years ago

Your boss has asked you to obtain marketing feedback on one of the products for your company produces. But people are less likel

babymother [125]

Answer:

no I won't follow my boss

because I don't use Fake information

5 0

2 years ago

A metallurgist has one alloy containing 26%26% copper and another containing 69%69% copper. How many pounds of each alloy must h

Brilliant_brown [7]

Answer:

Ans. He must use 2,987.76 pounds of alloy X (Cu=69%) and 2,365.24 pounds of alloy Y (26%=Cu)

Explanation:

Hi, let´s call alloy X the alloy that contains 69% of Cu and alloy Y the one containing 26% of Cu. Since he needs to produce 5,353 pounds of alloy, the first equation that we need to use is the following.

$X+Y=5,353$

Now, we need this 5,353 pounds of the new alloy to be 50% Cu, therefore, we have to use a portion of alloy X and alloy Y. This is as follows.

$0.69X+0.26Y=0.5(X+Y)$

And we have already established that X+Y is equal to 5,353, therefore this equation should look like this.

$0.69X+0.26Y=5,353*0.5$

$0.69X+0.26Y=2,676.5$

And we solve for X this equation, this as follows.

$0.69X=2,676.5-0.26Y$

$X=\frac{2,676.5-0.26Y}{0.69}$

$X=3,878.98-0.3768Y$

Now, we use this result and substitute this for X in the first equation like this.

$3,878.98-0.3768Y+Y=5,353$

and then, we solve for Y

$0.6232Y=5,353-3,878.98$

$Y=\frac{1,474.02}{0.6232} =2,365.24$

So, he needs to use 2,365.24 pounds of alloy that contains 26% of Cu, this means that the rest (2,987.76 pounds) must come from the alloy that contains 69% of Cu.

We can check this result by finding the overall Cu obtained by this amounts of alloy, that is

$Coppper FromX=2,987.76*0.69=2,061.55$

$Coppper FromY=2,365.24*0.26=614.96$

That adds up to 2,676.51 pounds of pure Cu, and since the total weight of the new alloy is 5,353, this amount of copper makes up for:

$PercentCu=\frac{2,676.51}{5,353} =0.5$

50% of the total weight.

Best of luck.

7 0

3 years ago