This is an easy one!
Three times a number = 128
3x = 128
x = 128/3
x = 42.66666.
Hope this helps!
<h3>
Answer: 16</h3>
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Explanation:
Equate s(t(x)) and s(1) to find that t(x) = 1 must be the case.
Let's find what x must be.
t(x) = 3x-8
1 = 3x-8
1+8 = 3x
9 = 3x
3x = 9
x = 9/3
x = 3
So plugging x = 3 into t(x) gets us t(x) = 1
In other words, t(3) = 1
So that tells us s(t(3)) = s(1)
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Let's plug x = 3 into the s(t(x)) equation
s(t(x)) = x^2 + 3x - 2
s(t(3)) = (3)^2 + 3(3) - 2
s(1) = 9 + 3(3) - 2
s(1) = 9 + 9 - 2
s(1) = 18 - 2
s(1) = 16
Answer: (0,−6),(1,−9/2),(2,−3)
I’m pretty sure these are it!
