Question

How many real solutions does the system have y=−3x−1 y=x^2−3x+4

Answer 1

Answer:

The system has no real solutions

Step-by-step explanation:

we have

$y=-3x-1$ ----> equation A

$y=x^{2}-3x+4$ ----> equation B

we know that

The solution of the system of equations is the intersection points both graphs

using a graphing tool

Graphics do not intersect

see the attached figure

therefore

The system has no real solutions