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4 years ago

Ayuden hijos mios :'v

Mathematics

2 answers:

frosja888 [35]4 years ago

8 0

What language is that

lana [24]4 years ago

3 0

Lo siento, lamentablemente no sé cómo responder

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ASAP HELP HELP HELP HELP HELP

Rasek [7]

He drove him for a total of 2 hours, 150 - 30 = 120

120 divided by 60 (60 minutes = 1 hour) = 2

8 0

4 years ago

Need the answer please and with work. I had put B but that is incorrect.

igor_vitrenko [27]

Answer:

Step-by-step explanation:

You answer goes to minus infinity. There is no answer and you are correct.

6 0

3 years ago

Assume the random variable X has a binomial distribution with the given probability of obtaining a success. Find the following p

Verizon [17]

Answer:

P(X = 17) = 0.3002

Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem we have that:

$n = 18, p = 0.9$

We want P(X = 17). So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 17) = C_{18,17}.(0.9)^{17}.(0.1)^{1} = 0.3002$

P(X = 17) = 0.3002

4 0

4 years ago

Read 2 more answers

Repeated addition: 1 3 + 1 3 + 1 3 = a b a = b =

IgorLugansk [536]

Answer:

Step-by-step explanation:

13 + 13 + 13 = 39

13 · 3 = 39

5 0

3 years ago

Read 2 more answers

PLEASE HELP!!!!! What is the value of x in the matrix equation below?

Brums [2.3K]

The given matrix equation is,

$1.5\left[\begin{array}{cc}x&6\\8&4\end{array}\right] +y\left[\begin{array}{cc}1&4\\3&2\end{array}\right] =\left[\begin{array}{cc}z&z\\6z&2\end{array}\right]$ .

Multiplying the matrices with the scalars, the given equation becomes,

$\left[\begin{array}{cc}1.5x&9\\12&6\end{array}\right] +\left[\begin{array}{cc}y&4y\\3y&2y\end{array}\right] =\left[\begin{array}{cc}z&z\\6z&2\end{array}\right] \\$

Adding the matrices,

$\left[\begin{array}{cc}1.5x+y&9+4y\\12+3y&6+2y\end{array}\right] =\left[\begin{array}{cc}z&z\\6z&2\end{array}\right] \\$

Matrix equality gives,

$1.5x+y=z\\ 9+4y=z\\ 12+3y=6z\\ 6+2y=2$

Solving the equations together,

$y=-2\\ 3y-1.5x=9\\ -1.5x=9+6\\ x=-10$

We can see that the equations are not consistent.

There is no solution.

3 0

3 years ago