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Anastasy [175]
3 years ago
10

Dany scored 93 in physics, 88 in mathematics, and a score in chemistry that is double his score in geography. The average score

of all 4 courses is 79. What were his scores in chemistry and geography?
Linda scored a total of 265 point
Mathematics
2 answers:
Leno4ka [110]3 years ago
6 0

Answer:

90

Step-by-step explanation:

Let x be Dany's score in geography. His score in chemistry is double his score in geography and it is equal to

2 x

The average of all four scores is 79. Hence

(93 + 88 + x + 2 x) / 4 = 79

Multiply both sides of the equation by 4

4×(93 + 88 + x + 2 x) / 4 = 4×79

Simplify

93 + 88 + x + 2 x = 316

Group like terms

3 x + 181 = 316

Solve for x

3 x = 135

3 x / 3 = 135 / 3

x = 45

score in geography = x = 45

score in chemistry = 2 x = 2 × 45 = 90

Hope it helped u if yes mark me BRAINLIEST!

Tysm!

barxatty [35]3 years ago
6 0

Answer:

\huge\boxed{Chem = 90 \ marks , Geo = 45 \ marks}

Step-by-step explanation:

Let the score of geography be x

=> Then, the score of chemistry will be 2x

So, the given condition is:

Average = \frac{Sum \ of \ values}{No. \ of \ values}

=> 79 = \frac{93+88+x+2x}{4}

=> 79 = \frac{181+3x}{4}

Multiplying both sides by 4

=> 79 * 4 = 181+3x

=> 316 = 181 + 3x

Subtracting 181 to both sides

=> 316-181 = 3x

=> 135 = 3x

Dividing both sides by 3

=> 45 = x

OR

=> x = 45

So,

Chemistry = 45 * 2 = 90 marks

Geography = 45 marks

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For each customer, there are only two possible outcomes, either they receive the coupon, or they do not. The probability of a customer receiving the coupon is independent of any other customer, which means that the binomial distribution is used to solve this question.

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A similar problem is given at brainly.com/question/25326823

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Step-by-step explanation:

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Answer:

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Split up this Isosceles, Right Triangle into two congruent smaller right triangles. The reflexive side [the line that splits them apart] is 6 units, and both legs are 8 units, leaving the hypotenuses to AUTOMATICALLY be 10 units, according to the Pythagorean Theorem:

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