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Arlecino [84]
3 years ago
11

How can I find out how to divide 1/2

Mathematics
2 answers:
borishaifa [10]3 years ago
6 0
Divide one half by what
IF your talking about this
100 divided by 1/2 then it would be 50 and all i did was put the multiply 100 by .5


kenny6666 [7]3 years ago
5 0
To divide one by two means to take one and split it in half. For example, if you have 1 pie and you / by 2. You took one whole pie and made two, half slices. 

Your result is; from one pie, you have two pieces, if you divide by five, you get five pieces. So on & so so forth. But be careful, because each time you divide more and more, the slices get smaller & smaller. Hope this helps.
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2 years ago
Suponha que uma variável assume os valores: 11 – 8 – 7 – a – 16 – 10 Determine a de modo que a média aritmética seja igual 11.
Elenna [48]

Answer:

a = 14  

Step-by-step explanation:

The mean is the sum of the values divided by the number of values.

\begin{array}{rcl}\text{Mean}&= &\dfrac{11 + 8 + 7 + a + 16 + 10}{6}\\\\\dfrac{52 + a}{6}& = & 11\\52 + a & = & 66\\a & = & 66 - 52\\& = & \mathbf{14}\\\end{array}

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3 years ago
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8 0
3 years ago
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What is the ratio for the volumes of two similar cylinders, given that the ratio of their heights and radii is 2:3?
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Step-by-step explanation:

4 0
3 years ago
The height H of an ball that is thrown straight upward from an initial position 3 feet off the ground with initial velocity of 9
mariarad [96]

Answer:

The ball will be 84 feet above the ground 1.125 seconds and 4.5 seconds after launch.

Step-by-step explanation:

Statement is incorrect. Correct form is presented below:

<em>The height </em>h(t)<em> of an ball that is thrown straight upward from an initial position 3 feet off the ground with initial velocity of 90 feet per second is given by equation </em>h(t) = 3 +90\cdot t -16\cdot t^{2}<em>, where </em>t<em> is time in seconds. After how many seconds will the ball be 84 feet above the ground. </em>

We equalize the kinematic formula to 84 feet and solve the resulting second-order polynomial by Quadratic Formula to determine the instants associated with such height:

3+90\cdot t -16\cdot t^{2} = 84

16\cdot t^{2}-90\cdot t +81 = 0 (1)

By Quadratic Formula:

t_{1,2} = \frac{90\pm \sqrt{(-90)^{2}-4\cdot (16)\cdot (81)}}{2\cdot (16)}

t_{1} = 4.5\,s, t_{2} = 1.125\,s

The ball will be 84 feet above the ground 1.125 seconds and 4.5 seconds after launch.

3 0
2 years ago
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