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Tomtit [17]
3 years ago
14

An object with a mass of 2.0kg accelerates 2.0m/s when an unknown force is applied. what is the amount of force?

Chemistry
1 answer:
FinnZ [79.3K]3 years ago
5 0
Force is equal to mass times acceleration. This means that the force applied to the object is 2 kg times 2.0 m/s, which gives you 4 Newtons.
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An unknown element "x" can form a compound with the formula "x"br2. in which main group on the periodic table would element "x"
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Group 2, or in the Alkaline Earth Metals section. This is due to the necessity to have a +2 charge to balance out or negate the -2 charge two Bromines carry.
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Water and carbon dioxide are similar because they both contain at least one oxygen
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Both have O
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Which civilization formed a confederation thay may have impacted the us government
lana66690 [7]

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Anasazi

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3 0
4 years ago
In each pair, choose the larger of the indicated quantities or state that the samples are equal:
romanna [79]

<u> There are more total ions in 2.2 moles of </u>MgCl_2

<h3>What are ions?</h3>

Ion, any atom or group of atoms that bears one or more positive or negative electrical charges. Positively charged ions are called cations; negatively charged ions, anions.

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Learn more about ions

brainly.com/question/13692734

#SPJ4

8 0
2 years ago
The​ half-life of​ plutonium-241 is approximately 13 years. a. How much of a sample weighing 2 g will remain after 70 ​years? b.
Studentka2010 [4]

Answer: A) 0.0480 grams and B) 56.16 years.

Explanation: Half live is the time in which the amount of radioactive substance remains halve of its initial amount.

The formula we use for solving this type of problem is:

\frac{N}{N_0}=(\frac{1}{2})^n

where, N_0 is the initial amount and N is the remaining amount of radioactive substance and n is the number of half lives.

n=T/t_1_/_2

where, T is the time and t_1_/_2 is half life.

A) from given data, N_0 = 2 g

T = 70 years

t_1_/_2 = 13 years

N= ?

n=\frac{70years}{13years}

n = 5.38

\frac{N}{2g}=(\frac{1}{2})^5^.^3^8

\frac{N}{2g}=0.0240

N = 0.0480 g

So, 0.0480 grams of the substance will be remaining after 70 years.

B) N_0 = 2 g

N = 0.1 g

T = ?

Let's first calculate the value of n for this.

\frac{0.1}{2}=(\frac{1}{2})^n

0.05=0.5^n

Taking log to both sides:

log0.05=nlog0.5

-1.301=n(-0.3010)

n=\frac{1.3010}{0.3010}

n = 4.32

Half life is 13 years, so we can calculate the time as:

n=T/t_1_/_2

T=n*t_1_/_2

T=4.32*13years

T = 56.16 years

So, it will take 56.16 years for the radioactive substance to decay from 2 g to 0.1 g.

8 0
4 years ago
Read 2 more answers
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