Density equals mas divided by volume. You know the density and mass so use it to solve for the volume.
d= m/v
d= 19.3 g/mL
m= 50g
v=?
Plug it in. 19.3= 50/v
To solve for v you do the opposite of 50 divided by v which is 50 time v.
That cancels v from the right side of the equation. Do the same on the other side(times v)
19.3 * v=50
Now just divide both sides by 19.3 to get v alone.
Answer:
Mrs. Nogaki is right because Mr. Holmes’s BBQ produces 3x more CO2 for each mole of fuel burned.
Explanation:
Now Mrs. Nogaki has already figured out the chemical combustion reaction behind the operation of her BBQ. It is pertinent to reproduce it here.
CH4(g) + 2O2(g)→CO2(g) +2H2O(g)
She already has this figured out but Mr. Holmes doesn't have any chemical reaction equation to back his claims. Let us help him with the correct combustion equation for propane.
C3H8(g) + 5O2(g) + 3CO2(g) + 4H2O(g)
We can clearly see from the reaction equation that Mr. Holmes BBQ produces three times more carbon IV oxide than Mr. Nogaki's BBQ so Mr. Nogaki was right in her claim after all.
Hence the answer!
Answer:
2.16 × 10⁻³
Explanation:
Step 1: Given data
Concentration of the acid (Ca): 0.260 M
Acid dissociation constant (Ka): 1.80 × 10⁻⁵
Step 2: Write the acid dissociation equation
HC₂H₃O₂(aq) + H₂O(l) ⇄ C₂H₃O₂⁻(aq) + H₃O⁺(aq)
Step 3: Calculate the concentration of H₃O⁺ at equilibrium
We will use the following expression.
![[H_3O^{+} ]= \sqrt{Ka \times Ca } = \sqrt{1.80 \times 10^{-5} \times 0.260 } = 2.16 \times 10^{-3}](https://tex.z-dn.net/?f=%5BH_3O%5E%7B%2B%7D%20%5D%3D%20%5Csqrt%7BKa%20%5Ctimes%20Ca%20%7D%20%3D%20%5Csqrt%7B1.80%20%5Ctimes%2010%5E%7B-5%7D%20%5Ctimes%200.260%20%7D%20%3D%202.16%20%5Ctimes%2010%5E%7B-3%7D)
Answer: pH = 10.92
Explanation:
To determine the pH of an aqueous solution, we use the following mathematical relation; pH = - log [H3O+]
= - log (6 x 10∧ -12)
= 12 - 1.08
pH = 10.92
