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docker41 [41]
3 years ago
12

What is 0.06% as a decimal and a fraction

Mathematics
2 answers:
mezya [45]3 years ago
6 0
<span>Step 1: 0.06 = 6⁄100</span> 
<span>Step 2: Simplify 6⁄100 = 3⁄50</span><span> 
hope this helps:)

</span>
Readme [11.4K]3 years ago
6 0
<span>
0.06%=0.06
0.06 as a fraction = 3/50</span>
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Rewards for answering the question below will be in place.
nadya68 [22]

Answer:

It is the distance that - 5 is from 0 on the number line.

Step-by-step explanation:

We have to select a statement that is true about the value of StartAbsoluteValue negative 5 EndAbsoluteValue i.e. |- 5|

Definition of the absolute value function is given by, |x| = x for, x ≥ 0 and |x| = - x for x < 0.

Now, an absolute value function gives the positive value of any value in the function i.e. |- 5| = 5.

Therefore, it is the distance that - 5 is from 0 on the number line. (Answer)

6 0
3 years ago
Read 2 more answers
Which choice is equivalent to the quotient below shown here when x&gt;0?
qwelly [4]

Answer:

Choice B is correct

Step-by-step explanation:

The given radical division can be expressed in the following form;

\frac{\sqrt{16x^{3} } }{\sqrt{8x} }

Using the properties of radical division, the expression can be expressed in the following form;

\sqrt{\frac{16x^{3} }{8x} }=\sqrt{2x^{2} }

Simplifying further yields;

\sqrt{2x^{2} }=\sqrt{2}*\sqrt{x^{2} }=x\sqrt{2}

Choice B is thus the correct alternative

5 0
3 years ago
Read 2 more answers
A discuss moves from P1 (4,8) to P2 (15,17). What is the lincar displacement in the horizontal and vertical directions? What is
Yakvenalex [24]

Answer:

The horizontal displacement is 11 units, the vertical displacement is 9 units, and the projection angle is 39.3 degrees.

Step-by-step explanation:

We can start using the definition of displacement in one dimension between any 2 points which is the difference between them, so we have

\Delta s = s_2-s_1

And apply it to get the horizontal and vertical displacements.

Once we have found them, we can use trigonometric functions to find the projection angle with respect the horizontal.

Linear displacements.

Using the definition of displacement, we can write the horizontal displacement as

\Delta x = x_2-x_1

So we can use the given points P1:(x_1,y_2)  \text{  and  } P_2: (x_2,y_2) on the displacement formula

\Delta x = 15-4\\\Delta x = 11

In the same manner we can look at the y components of those points to find the vertical displacement

\Delta y = 17-8\\\Delta y =9

Thus the horizontal displacement is 11 units and the vertical displacement is 9 units.

Projection angle.

The projection angle with respect the horizontal is the angle that is made between the line that connects the points P1 and P2 and the horizontal, so we can use the linear displacements previously found to write

\tan(\theta) = \cfrac{\Delta y}{\Delta x}

Solving for the angle we get

\theta = \tan^{-1}\left(\cfrac{\Delta y}{\Delta x}\right)

Replacing values

\theta = \tan^{-1}\left(\cfrac{9}{11}\right)

Which give us

\theta = 39.3^\circ

So the projection angle is 39.3 degrees.

7 0
3 years ago
I don't know how to do this
vesna_86 [32]
He could have 30 dimes and 13 quartars
7 0
3 years ago
WVXZ is a parallelogram. Given that &lt;ZXV = 70° and &lt;WZX =4y+34, find y and m&lt;Z​
rjkz [21]

Answer:

WZX = 110

y = 19

Step-by-step explanation:

We can create the following equation to solve for y.

4y + 34 + 70 = 180

Reduce

4y = 76

y = 19

We then plug into 4y + 34 to get angle

WZX = 110

5 0
3 years ago
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