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lesantik [10]
3 years ago
13

Please help. the question is in the picture.

Mathematics
2 answers:
Harlamova29_29 [7]3 years ago
8 0

We have measures of all tree sides of the both triangles,

so we can use SSS to check if the triangles are similar.

|ED|/|AB| =5/10=1/2

|DC|/|BC| = 4/8 = 1/2

|EC|/|AC| = 6/12 = 1/2

We see that all tree pairs are in proportion, so these triangles ΔABC and ΔEDC are similar.

We have enough information to prove that ΔABC similar to ΔEDC.

Ugo [173]3 years ago
5 0

We see E is a midpoint so AC:EC=2:1

So our scale factor for similarity must be 2. Let's check the other two sides

AB:ED = 10:5 = 2:1 good

BC:DC = 8:4 = 2:1 good

Each side of ABC is twice its respective side of EDC, so we've shown they're similar.

Answer: Yes


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Find the 12th term of the following geometric sequence.<br> 10, 30, 90, 270,
DanielleElmas [232]

Answer:

<h3>The 12th term is 1771470</h3>

Step-by-step explanation:

Since the above sequence is a geometric sequence

An nth term of a geometric sequence is given by

A(n) = a(r)^{n - 1}

where a is the first term

r is the common ratio

n is the number of terms

From the question

a = 10

To find the common ratio divide the previous term by the next term

That's

r = 30/10 = 3 or 90/30 = 3 or 270/90 = 3

Since we are finding the 12th term

n = 12

So the 12th term is

A(12) = 10( {3})^{12 - 1}

A(12) = 10 ({3})^{11}

<h3>A(12) = 1771470</h3>

Hope this helps you

8 0
3 years ago
The scale drawing of a concrete pad has a length of 9.1 cm, a depth of 2.2 cm and a width of 3.8 cm.
pogonyaev

Answer:

242 cm  

Step-by-step explanation:

1. Find the scale factor

A scale factor (SF) is the ratio of two corresponding lengths in similar figures.

SF = actual distance/scale distance

If the scale width is 3.8 cm,

SF = 418 cm/3.8 cm = 110

2. Calculate the actual depth

110 = actual depth/2.2 cm

Actual depth = 110 × 2.2 cm = 242 cm

8 0
3 years ago
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3 years ago
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rank has a circular garden. The area of the garden is 100 ft2. What is the approximate distance from the edge of Frank’s garden
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It is given that the area of the circular garden = 100 ft^2

Area of circle with radius 'r' = \pi r^2

We have to determine the approximate distance from the edge of Frank’s garden to the center of the garden, that means we have to determine the radius of the circular garden.

Since, area of circular garden = 100

\pi r^2 = 100

\frac{22}{7} \times r^2 = 100

r^2 = \frac{700}{22}

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r = \sqrt{31.8}

So, r = 5.6 ft

r = 6 ft (approximately)

Therefore, the approximate distance from the edge of Frank’s garden to the center of the garden is 6 ft.

So, Option A is the correct answer.

7 0
3 years ago
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Answer:

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Step-by-step explanation:

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Each friend has to pay $6.37 each if $25.48 is splitted evenly amongst them

6 0
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