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Hi, you can get 15 points if you answer this...

RSB [31]

Answer:

Si

Step-by-step explanatio:

4 0

3 years ago

Read 2 more answers

What is a binomial polynomial?

Gemiola [76]

Answer:

a binomial is a polynomial that is the sum of two terms, each of which is a monomial. It is the simplest kind of polynomial after the monomials.

8 0

3 years ago

The width of a casing for a door is normally distributed with a mean of 24 in and a standard deviation of 0.14 in. The width of

Galina-37 [17]

Answer:

0.2296 = 22.96% probability that the width of the casing exceeds the width of the door by more than 0.25 in.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Subtraction of normal variables:

When we subtract normal variables, the mean is the subtraction of the means, while the standard deviation is the square root of the sum of the variances.

The width of a casing for a door is normally distributed with a mean of 24 in and a standard deviation of 0.14 in.

This means that $\mu_{C} = 24, \sigma_{C} = 0.14$

The width of a door is normally distributed with a mean of 23.87 in and a standard deviation of 0.08 in.

This means that $\mu_{D} = 23.87, \sigma_{D} = 0.08$ .

Find the probability that the width of the casing exceeds the width of the door by more than 0.25 in?

This is P(C - D > 0.25).

Distribution C - D:

The mean is:

$\mu = \mu_{C} - \mu_{D} = 24 - 23.87 = 0.13$

The standard deviation is:

$\sigma = \sqrt{\sigma_{C}^2+\sigma_{D}^2} = \sqrt{0.14^2+0.08^2} = 0.1612$

Probability:

This probability is 1 subtracted by the pvalue of Z when X = 0.25. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{0.25 - 0.13}{0.1612}$

$Z = 0.74$

$Z = 0.74$ has a pvalue of 0.7704

1 - 0.7704 = 0.2296

0.2296 = 22.96% probability that the width of the casing exceeds the width of the door by more than 0.25 in.

4 0

3 years ago

If f(x) = x2 – 1 and g(x) = 2x – 3, what is the domain of (fºg)(x)?

astra-53 [7]

Answer:

(fog)(x)= 2(2x-3) - 1

(fog)(x)= 4x -6 - 1

(fog)(x)= 4x - 7

Domain of (fog)(x)= 4x-7

(-00,00)

6 0

3 years ago

These figures are similar. The perimeter and

jok3333 [9.3K]

Answer:

56.644 m^2

Step-by-step explanation:

It's a rule that if the ratio of the sides of 2 similar figures is a:b, the ratio of their areas is a^2:b^2. (I may not be using the standard variables or the exact wording here, but that's the basic idea.)

You can simplify this and understand it with squares. All squares are similar, right? Imagine a 2 in. by 2 in. square and a 4 in. by 4 in. square. The ratio of their sides is 2:4, or 1:2. (The ratio of their perimeters is the same thing. 2*4=8 inches for the smaller square, and 4*4=16 for the bigger square. 8:16=1:2) The ratio of their areas is 4:16, or 1:4. (1/2)^2=1/4

The same thing applies here. The perimeter of the larger figure divided by the perimeter of the smaller one is 34/20=1.7. That means that the area of the larger figure divided by the area of the smaller one is 1.7^2, or 2.89. You can write an equation where x is the area of the larger one:

x/19.6=2.89

x=56.644 m^2

Hope I could help you!

8 0

3 years ago