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crimeas [40]
4 years ago
10

A, B, C are circular regions as shown below. There are 7 items in C and there are 20 items in A but 10 of those items are not in

B. How many items are in B that are not in C

Mathematics
1 answer:
Elenna [48]4 years ago
3 0

Answer:

3 items are in B that are not in C

Step-by-step explanation:

a: only in a, not count those in b or c

b: only in b, not count those in a or c

c: only in c, not count those in a or b

A = a + b + c = 20

c = 7

a + b = 20 - 7 = 13

10 not in b, of course not in c ∴ a = 10

b = 13 -10 = 3

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3 years ago
What is the equivalent ratios of 10:100
SSSSS [86.1K]
1:10 or 100:1000 so the point is to just add one zero to each side and you'll get it right
5 0
4 years ago
Use the figure above to solve for x
Fiesta28 [93]

Answer:

x is equal to 7

Step-by-step explanation:

Because the two horizontal lines are parallel, we know that the angles at which they intersect the diagonal line will be identical.

We also know that on either side of the diagonal line, the sum of the angles between that and either of the horizontal lines will be 180.

In short, we know that the two values given have a sum of 180.  With that we can quickly solve for x:

(x + 67) + (x + 127) = 180

2x + 194 = 180

2x = -14

x = 7

6 0
3 years ago
SOLVING EACH SYSTEM BY ELIMINATION <br><br><br> x+3y=5 x=-6y+14<br><br><br> HELP
nata0808 [166]

Answer:

\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}

x=-4,\:y=3

Step-by-step explanation:

Given the system of the equations

x+3y=5;\:x=-6y+14

solving by elimination method

\begin{bmatrix}x+3y=5\\ x=-6y+14\end{bmatrix}

\mathrm{Arrange\:equation\:variables\:for\:elimination}

\begin{bmatrix}x+3y=5\\ x+6y=14\end{bmatrix}

x+6y=14

-

\underline{x+3y=5}

3y=9

\begin{bmatrix}x+3y=5\\ 3y=9\end{bmatrix}

solve 3y=9 for y:

3y=9

\frac{3y}{3}=\frac{9}{3}

y=3

\mathrm{For\:}x+3y=5\mathrm{\:plug\:in\:}y=3

Solve x+3\cdot \:3=5 for x:

x+3\cdot \:3=5

x+9=5

x=-4

Therefore,

\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}

x=-4,\:y=3

6 0
3 years ago
The cost of a candy bar in a vending machine is $0.95. The cost of a bottle of water in the same machine is $1.25. Jamie has $25
den301095 [7]

Answer:

The answer is $16.45


Step-by-step explanation:

First, you have to multiply $0.95 x 9 = $8.55


Then, you have to subtract $25.00-$8.55 = $16.45




5 0
4 years ago
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