First, you have to substitute for x, which would make the problem f(x)=7.45(-4.3)+33.7
Now, you just have to use the PEMDAS method (Parenthesis, Exponents, Multiplication, Division, Addition, Subtraction)
f(x)= -32.035+33.7
f(x)=1.665
complette the square to get vertex form or y=a(x-h)^2+k
(h,k) is vertex
1. group x terms, so for y=ax^2+bx+c, do y=(ax^2+bx)+c
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2, factor out the leading coefinet (constant in front of the x^2 term), basicallly factor out a
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3. take 1/2 of the linear coefient (number in
front of the x), and square it ,then add negative and positive of it
inside parnthases
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4. complete the squre and expand
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so
y=-1/4x^2+4x-19
group
y=(-1/4x^2+4x)-19
undistribute -1/4
y=-1/4(x^2-16x)-19
take 1/2 of -16 and squer it to get 64 then add neg and pos inside
y=-1/4(x^2-16x+64-64)-19
factorperfect square
y=-1/4((x-8)^2-64)-19
expand
y=-1/4(x-8)^2+16-19
y=-1/4(x-8)^2-3
vertex is (8,-3)
Answer:
Put this table into Desmos and then wherever the line crosses the y-axis, is your y-intercept.
Answer:
y^3 - y + 6
Step-by-step explanation:
I believe this is right
Answer:
<em>y = -2/3 x + 1</em>
Step-by-step explanation:
The line y = -2/3 x + 5 is in y = mx + b form, where m is the slope, so the slope of the given line is -2/3. Parallel lines have equal slopes, so the equation you are looking for also has slope -2/3.
The parallel line has equation
y = -2/3 x + b
We need to find b.
Since we are given a point, we substitute x and y with the x- and y-coordinates of the given point and solve for b. x = 6, and y = -3.
y = -2/3 x + b
-3 = (-2/3)(6) + b
-3 = -4 + b
1 = b
Now that we know b = 1, we can write the equation.
y = -2/3 x + b
y = -2/3 x + 1
