The cost of electricity consumed by the TV per month is <u>$4.968</u>.
In the question, we are given that a TV set consumes 120W of electric power when switched on. It is kept on for a daily average of 6 hours per day. The number of days in the month is given to be 30 days. The cost per unit of electricity is 23 cents per kWh.
We are asked to find the cost of electricity the TV consumes in the month.
The daily energy consumed by the TV = Power*Daily time = 120*6 Wh = 720 Wh.
The monthly energy consumed by the TV = Daily energy*Number of days in the month = 720*30 Wh = 21600 Wh = 21600/1000 kWh = 21.6 kWh.
Hence, the total cost of electricity the TV consumes = Monthly energy*Per unit cost = 21.6*23 cents = 496.8 cents = $496.8/100 = $4.968.
Therefore, the cost of electricity consumed by the TV per month is <u>$4.968</u>.
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Answer:
guitarist a&b I often their service to throne but each guitarist charge different intentional feeds and hourly rates how can the throne check to see when they will charge the same amount of money named three ways to perform this task answer
A proportional relationship would look like y=mx (no y-intercept).
The formula for temperature Fahrenheit involves an offset (y-intercept); this is one reason I claim that the relationship in question is NOT proportional.
Based on the given original and dilated points, you can notice that the dilation is:
(x,y) => (1/3 x , 1/3 y)
This can be verified with any point of the figure, for example:
C(6,-3) => C'(1/3 (6) , 1/3 (-3)) = C'(2 , -1)
Hence, the answer is:
(1/3 x , 1/3 y)
Answer:
sin θ/2=5√26/26=0.196
Step-by-step explanation:
θ ∈(π,3π/2)
such that
θ/2 ∈(π/2,3π/4)
As a result,
0<sin θ/2<1, and
-1<cos θ/2<0
tan θ/2=sin θ/2/cos θ/2
such that
tan θ/2<0
Let
t=tan θ/2
t<0
By the double angle identity for tangents
2 tan θ/2/1-(tanθ /2)^2 = tanθ
2t/1-t^2=5/12
24t=5 - 5t^2
Solve this quadratic equation for t :
t1=1/5 and
t2= -5
Discard t1 because t is not smaller than 0
Let s= sin θ/2
0<s<1.
By the definition of tangents.
tan θ/2= sin θ/2/ cos θ/2
Apply the Pythagorean Algorithm to express the cosine of θ/2 in terms of s. Note the cos θ/2 is expected to be smaller than zero.
cos θ/2 = -√1-(sin θ/2)^2 = - √1-s^2
Solve for s.
s/-√1-s^2 = -5
s^2=25(1-s^2)
s=√25/26 = 5√26/26
Therefore
sin θ/2=5√26/26=0.196....
