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3 years ago

How do you write a paragraph proof to prove that the corresponding angles shown are congruent

Mathematics

2 answers:

iVinArrow [24]3 years ago

8 0

Answer:

write how u sovled the problem step by step

Step-by-step explanation:

fredd [130]3 years ago

5 0

To prove this statement, start with a picture of alternate interior angles that are assumed to be congruent, but don't assume the lines are parallel. In the picture below, assume . Prove that (two parallel bars indicate parallel lines). If corresponding angles are congruentthen lines are parallel.

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A pack of 6 batteries of the same type cost £2.79 By calculating the price per battery,

maks197457 [2]

$\large{\rm{\underline{\underline{Answer:}}}}$

Given, 6 batteries for £2.79

(They are of same type, so each of them are of same cost. )

~Simply divide the total price of 6 batteries by 6 to get the price of each battery,

$= \dfrac{£2.79 }{6}$

$= £ \dfrac{279}{100 \times 6}$

$= £ \dfrac{46.5}{100}$

$= £0.465$

Thus, cost of each battery is £ 0.465 (ans)

8 0

2 years ago

Solve the equation Hey guys can i get some help on this one? thanks!

eimsori [14]

Answer:

look at the picture i have sent

8 0

3 years ago

In what time will the interest on $960 amount to $61.20 at 8.5% per annum?

MrRa [10]

Answer:

$525 dollars

Step-by-step explanation:

5 0

2 years ago

A gas is said to be compressed adiabatically if there is no gain or loss of heat. When such a gas is diatomic (has two atoms per

Tems11 [23]

Answer:

The pressure is changing at $\frac{dP}{dt}=3.68$

Step-by-step explanation:

Suppose we have two quantities, which are connected to each other and both changing with time. A related rate problem is a problem in which we know the rate of change of one of the quantities and want to find the rate of change of the other quantity.

We know that the volume is decreasing at the rate of $\frac{dV}{dt}=-4 \:{\frac{cm^3}{min}}$ and we want to find at what rate is the pressure changing.

The equation that model this situation is

$PV^{1.4}=k$

Differentiate both sides with respect to time t.

$\frac{d}{dt}(PV^{1.4})= \frac{d}{dt}k\\$

The Product rule tells us how to differentiate expressions that are the product of two other, more basic, expressions:

$\frac{d}{{dx}}\left( {f\left( x \right)g\left( x \right)} \right) = f\left( x \right)\frac{d}{{dx}}g\left( x \right) + \frac{d}{{dx}}f\left( x \right)g\left( x \right)$

Apply this rule to our expression we get

$V^{1.4}\cdot \frac{dP}{dt}+1.4\cdot P \cdot V^{0.4} \cdot \frac{dV}{dt}=0$

Solve for $\frac{dP}{dt}$

$V^{1.4}\cdot \frac{dP}{dt}=-1.4\cdot P \cdot V^{0.4} \cdot \frac{dV}{dt}\\\\\frac{dP}{dt}=\frac{-1.4\cdot P \cdot V^{0.4} \cdot \frac{dV}{dt}}{V^{1.4}} \\\\\frac{dP}{dt}=\frac{-1.4\cdot P \cdot \frac{dV}{dt}}{V}}$

when P = 23 kg/cm2, V = 35 cm3, and $\frac{dV}{dt}=-4 \:{\frac{cm^3}{min}}$ this becomes

$\frac{dP}{dt}=\frac{-1.4\cdot P \cdot \frac{dV}{dt}}{V}}\\\\\frac{dP}{dt}=\frac{-1.4\cdot 23 \cdot -4}{35}}\\\\\frac{dP}{dt}=3.68$

The pressure is changing at $\frac{dP}{dt}=3.68$ .

7 0

3 years ago

Please help..I dont get this and please Dont put a Link below please.

lianna [129]

Answer:

x = 27, y = 74

Step-by-step explanation:

Hi again :)

Since the angles of 5x + 4 and the one adjacent to x = 14 are corresponding angles, they are equal. That means that (5x + 4) + (x + 14) = 180 degrees.

5x + 4 + x + 14 = 180

6x + 18 = 180

6x = 162

x = 27

Also, the angle (5x + 4) and (2y - 9) are vertical angles, they are equal in value. We know the value of x now, so we'll substitute that in and solve for y.

5(27) + 4 = 2y - 9

135 + 4 = 2y - 9

139 = 2y - 9

148 = 2y

y = 74

As always, lmk if you have questions.

3 0

3 years ago