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german
3 years ago
10

What is the range of possible sizes for sides x 3.2 and 5.5

Mathematics
1 answer:
Effectus [21]3 years ago
7 0
5.5 to the 5th power
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The area of a rectangle is 72 cm square. The length of the rectangle is 6 cm longer than the width. What is the width of the rec
miskamm [114]

The correct option will be :  B) 6 cm.

<u><em>Explanation</em></u>

Suppose, the width of the rectangle is x cm.

As, the length is 6 cm longer than the width, so the length will be: (x+6) cm.

<u>Formula for the Area of rectangle</u> is: (Length)*(Width)

Given that, the area of a rectangle is 72 cm²

So....

x(x+6)=72\\ \\ x^2+6x-72=0\\ \\ (x+12)(x-6)=0

Using zero-product property, we will get...

x+12=0\\ x= -12 <em>(Negative value is ignored as width can't be negative)</em>

and

x-6=0\\ x=6

So, the width of the rectangle is 6 cm.

6 0
3 years ago
What is the circumference of the circle if r = 3,5 feet?
Nady [450]

Answer:

21.98

Step-by-step explanation:

C=2πr C=2d are the formulas of circumference so that would mean the diameter of the circle is 7 since 2 times the radius is the diameter. We then multiply the diameter 7 by PI to get 21.98

8 0
3 years ago
In A ABC, side AB is included between<br> angles A and C<br> angles B and C<br> angles A and B
Artist 52 [7]

Answer:

angles A and B

Step-by-step explanation:

the side of a triangle is denoted by naming with its vertices that are joined in forming the side. so here vertices A and B are included for side AB.

∴ The angles included are A and B

4 0
3 years ago
Somebody explain pls!!!!!
Furkat [3]

Step-by-step explanation:

Using log properties

log_{7}(rz {}^{12} )

log_{7}(r)  +  log_{7}(z {}^{12} )

Then

log_{7}(r)  + 12 log_{7}(z)

Plug in the knowns

- 7.87 + 12( - 12.59)

- 158.95

5 0
1 year ago
Eric has 183 coins all of them are nickels and dimes. If the total value of the coins is 14.45, how many of each denomination co
FromTheMoon [43]

Answer:

77 nickels

106 dimes

Step-by-step explanation:

Let there be n nickes and d dimes

Since there are 183 coins, we can write:

n + d = 183

Also, the value of nickel is 0.05 and dime is 0.1, total value is 14.45, so we can write:

0.05n + 0.1d = 14.45

Solving 1st equation for n, we have:

n = 183 - d

Putting this into 2nd equation and solving for d:

0.05n + 0.1d = 14.45\\0.05(183-d) + 0.1d = 14.45\\9.15-0.05d+0.1d=14.45\\0.05d=5.3\\d=106

There are 106 dimes

Since, n = 183 - d

n = 183 - 106

n = 77

There are 77 nickels

4 0
3 years ago
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