3 years ago

Can you help me please

Mathematics

1 answer:

grigory [225]3 years ago

5 0

m is 43

add my instagarm @jessica.letendre

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<img src="https://tex.z-dn.net/?f=%28x%20-%203%29%28x%20%2B%204%29%28x%20-%202%29%20%3D%200" id="TexFormula1" title="(x - 3)(x +

AlexFokin [52]

Answer:

Step-by-step explanation:

x-3 = 0

x = 3

x + 4 = 0

x = -4

x - 2 = 0

x = 2

x = 3, -4, 2

8 0

3 years ago

Two of the solutions for the equation 2x + 3y = 12 are (9, ? ) and ( ? , 4).

brilliants [131]

I got 30, I’m not sure if it’s correct or not.

4 0

2 years ago

Read 2 more answers

Please help me with this question :)

egoroff_w [7]

Answer:

Plot $3$ and $-3$

Step-by-step explanation:

Given:

$|2n| = 6$

Solving for the positive part of the equation:

$2n = 6 \\ \frac{2n}{2} = \frac{6}{2} \\ n = 3$

Solving for the negative part of the equation:

$-2n = 6 \\ \frac{-2n}{-2n} = \frac{6}{-2} \\ n = -3$

3 0

2 years ago

A hyperbola centered at the origin has a vertex at (0,−40) and a focus at (0, 41).

aniked [119]

$\frac{(x-h)^{2} }{a^{2} } - \frac{(y - k)^{2} }{b^{2} } = 1$

$\frac{(x-0)^{2} }{40^{2} } - \frac{(y - 0)^{2} }{b^{2} } = 1$

a² + b² = c²

40² + b² = 41²

b² = 41² - 40²

b² = 1681 - 1600

b² = 81

b = 9

slope (m) of asymptote = $+/-\frac{y}{x} = +/-\frac{b}{a} = +/-\frac{9}{40}$

y-intercept (b) = 0 since the center is at the origin

Answer: y = $\frac{9}{40}x$ and y = $-\frac{9}{40}x$

7 0

2 years ago

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What is the value of the expression 2,160/30

tester [92]

Answer:

Step-by-step explanation:

8 0

3 years ago