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If point T was located at 4,6 and moved 3 units to the left and 2 units down, at what coordinations will point T be located
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Answer:
We have the function,
On simplifying, we get,
i.e.
Thus, the standard form of the function is .
Now, the factors of the given functions are (x+1) and (x+5).
<em>Since, the intercept form of the function is the factored form of the function.</em>
So, we have, intercept form of the function is .
Now, we know that,
Value of x-coordinate of the vertex is i.e.
i.e.
i.e. x= -3
Then, i.e.
i.e. f(-3)=-4
So, the vertex of the function is (-3,-4).
Further, we know that,<em> 'the y-intercept of a function is the point where the function crosses y-axis'.</em>
So, when x=0, we have, i.e. f(0) = 5
Thus, the y-intercept is (0,5)
Also, <em>'the x-intercept of a function is the point where the function crossese x-axis'.</em>
Then, for f(x)=0, we have i.e.
i.e. x= -1 and x= -5
Thus, the x-intercept are (-1,0) and (-5,0).