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solong [7]
3 years ago
9

Write a function that receives an integer list from STL and returns the sum of even numbers in the list (return zero if no even

number is in the list)
Computers and Technology
1 answer:
Doss [256]3 years ago
8 0

Answer:

int sumeven(int lis[],int n)

{

   int sum_e=0;//integer variable to store the sum.

   for(int i=0;i<n;i++)

       {

           if(lis[i]%2 == 0)//if the number is even adding to sum_e.

           sum_e=sum_e+i;

       }

   return sum_e;//retuning the sum.

   

}

Explanation:

The above written function is in C++.This function find the sum of even numbers in the list provided.It loops over the array and if the number is even adds to the variable sum_e finally return sum_e which having the sum of even numbers now.

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side or back lighting

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hope it helps!

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How can knowing internal and external parts of computer help me
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A deluxe meal, represented by a DeluxeMeal object, includes a side dish and a drink for an additional cost of $3. The DeluxeMeal
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DeluxeMeal burritoCombo = new DeluxeMeal ("burrito", "chips", "Lemonade", 7.49);

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4 0
3 years ago
Drag each statement to the correct location.
VMariaS [17]

Answer:

(a)\ 222_{10} = DE_{16} --- True

(b)\ D7_{16} = 11010011_2 --- False

(c)\ 13_{16} = 19_{10} --- True

Explanation:

Required

Determine if the statements are true or not.

(a)\ 222_{10} = DE_{16}

To do this, we convert DE from base 16 to base 10 using product rule.

So, we have:

DE_{16} = D * 16^1 + E * 16^0

In hexadecimal.

D =13 \\E = 14

So, we have:

DE_{16} = 13 * 16^1 + 14 * 16^0

DE_{16} = 222_{10}

Hence:

(a) is true

(b)\ D7_{16} = 11010011_2

First, convert D7 to base 10 using product rule

D7_{16} = D * 16^1 + 7 * 16^0

D = 13

So, we have:

D7_{16} = 13 * 16^1 + 7 * 16^0

D7_{16} = 215_{10}

Next convert 215 to base 2, using division rule

215 / 2 = 107 R 1

107/2 =53 R 1

53/2 =26 R1

26/2 = 13 R 0

13/2 = 6 R 1

6/2 = 3 R 0

3/2 = 1 R 1

1/2 = 0 R1

Write the remainders from bottom to top.

D7_{16} = 11010111_2

<em>Hence (b) is false</em>

(c)\ 13_{16} = 19_{10}

Convert 13 to base 10 using product rule

13_{16} = 1 * 16^1 + 3 * 16^0

13_{16} = 19

Hence; (c) is true

7 0
3 years ago
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