Is it possible to have a solution that has 1 real and 1complex root?

Mathematics

1 answer:

Volgvan3 years ago

8 0

Answer:

Step-by-step explanation:

It is not possibe! you have to have a soulution that has 3 real and 1 complex root!

It does not make sence!

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Could you help me with number 18

Travka [436]

The better bargain is the 4 quarts

6 0

3 years ago

5 + 6 - (-3) - 8 + 4 -3

Komok [63]

Okay, so -

We have one very important thing here. This little part 6 - (-3). 

Now, it's essential to remember that when we have two negatives like this, we simply draw a line straight down. It becomes a positive!

So, our question is essentially 5 + 6 + 3 - 8 + 4 - 3 = ? instead of 5 + 6 - (-3) - 8 + 4 - 3! =)

With that in mind, we simply solve left to right.

11 + 3 - 8 + 4 - 3 = ?

14 - 8 + 4 - 3 = ?

6 + 4 - 3 = ?

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7 is our final answer! =)

6 0

3 years ago

Suppose a university advertises that its average class size is 34 or less. A student organization is concerned that budget cuts

Korolek [52]

Answer:

H0: μ ≤ 34

H1: μ > 34

The z-test statistic is ≈ 1.8

The critical z-score is 1.28

we fail to reject the null hypothesis H0: μ ≤ 34

Step-by-step explanation:

H0: μ ≤ 34