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romanna [79]
3 years ago
12

Is it possible to have a solution that has 1 real and 1complex root?

Mathematics
1 answer:
Volgvan3 years ago
8 0

Answer:

No

Step-by-step explanation:

It is not possibe! you have to have a soulution that has 3 real and 1 complex root!

It does not make sence!

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Sweet T is making a double batch of cupcakes. He puts them in the oven at 6:50 that needs to bake for 25 minutes. When should sw
Serhud [2]
He should take out the cupcakes at 7:15! Hope this helps :D
8 0
3 years ago
Solve for X<br> (5x-2)^2=17<br> please help me everyone.
beks73 [17]

Answer:

\frac{2}{5}±\frac{\sqrt{17}}{5}

Step-by-step explanation:

(5x-2)^2=17 \\ 5x-2=±\sqrt{17} \\ 5x = 2 ± \sqrt{17}   \\ x=\frac{2}{5}± \frac{\sqrt{17}}{5}

Don't mind the ±

5 0
3 years ago
Simplify the expression to one number using order of operations:
geniusboy [140]
<h2><u>COMBINED OPERATIONS</u></h2><h3>Exercise</h3>

First, let's solve the subtraction (in parentheses):

\mathsf{\dfrac{-8\left(2-6\right)}{2}}

\mathsf{\dfrac{-8(-4)}{2}}

Now, let's solve the multiplication. Remember: in multiplication, two negative numbers will give a positive number:

\mathsf{\dfrac{-8(-4)}{2}}

\mathsf{\dfrac{32}{2}}

Finally, let's solve the division:

\mathsf{\dfrac{32}{2} = 16}

<h3><u>Answer</u>: 16</h3>
5 0
3 years ago
How do i solve this inequality? Number 46
myrzilka [38]
6(x-2.5) ≥ 8-6(3.5+x)

A number is before a parenthesis. The first step is to multiply.

6(x-2.5) = 6x -15

8-6(3.5+x)
2(3.5+x)= 7+2x

6x-15≥7+2x

Now solve

6x-15≥7+2x
-2x -2x

(-2x+2x)= They cancel out

(6x-2x)= 4x

4x-15≥7
+15 +15

4x≥22
/4 /4

You get= x≥5.5
7 0
3 years ago
(5+4-2)×(-2)=idfkadtsphm
lbvjy [14]
5+4=9   9-2=7 

7x(-2)= (-14)

your answer is -14

6 0
3 years ago
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