62.5 mg sample will remain after 240 days
Step-by-step explanation:
Given
Half-life = T = 60 days
The formula for calculating the quantity after n half lives is given by:
![N = N_0(\frac{1}{2})^n](https://tex.z-dn.net/?f=N%20%3D%20N_0%28%5Cfrac%7B1%7D%7B2%7D%29%5En)
Here
N is the final amount
N_0 is the initial amount
n is the number of half lives passed
The number of half lives are calculated by dividing the time for which the remaining quantity has to be found by half life
The quantity has to be calculated for 240 days so,
![n = \frac{240}{60}\\n = 4](https://tex.z-dn.net/?f=n%20%3D%20%5Cfrac%7B240%7D%7B60%7D%5C%5Cn%20%3D%204)
Given
![N_0 = 1000\ mg](https://tex.z-dn.net/?f=N_0%20%3D%201000%5C%20mg)
Putting the values in the formula
![N = 1000 (\frac{1}{2})^4\\=1000 * \frac{1}{16}\\=\frac{1000}{16}\\=62.5\ mg](https://tex.z-dn.net/?f=N%20%3D%201000%20%28%5Cfrac%7B1%7D%7B2%7D%29%5E4%5C%5C%3D1000%20%2A%20%5Cfrac%7B1%7D%7B16%7D%5C%5C%3D%5Cfrac%7B1000%7D%7B16%7D%5C%5C%3D62.5%5C%20mg)
Hence,
62.5 mg sample will remain after 240 days
Keywords: Half-life, sample
Learn more about half-life at:
#LearnwithBrainly
Answer:
Whats the question
Step-by-step explanation:
Answer:
<u>D.</u>
Step-by-step explanation:
You just have to try it out for some points. I tried it for (-4,-3), (0,0), (7,0)
Answer: (0,1), (1,0)
Step-by-step explanation:
plug in a number for y.
ex) x=0 y=1
y=-x + 1
1= -0 + 1
1=0 + 1
Answer:
Step-by-step explanation:
1. The given equation is:
![\frac{3}{5}{\times}\frac{4}{5}](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B5%7D%7B%5Ctimes%7D%5Cfrac%7B4%7D%7B5%7D)
Multiplying both the terms, we get
![\frac{12}{25}](https://tex.z-dn.net/?f=%5Cfrac%7B12%7D%7B25%7D)
Option A is correct.
2. The given equation is:
![2\frac{1}{3}{\times}\frac{3}{4}](https://tex.z-dn.net/?f=2%5Cfrac%7B1%7D%7B3%7D%7B%5Ctimes%7D%5Cfrac%7B3%7D%7B4%7D)
Converting the improper fraction into the mixed fraction,
![\frac{7}{3}{\times}\frac{3}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B7%7D%7B3%7D%7B%5Ctimes%7D%5Cfrac%7B3%7D%7B4%7D)
=![\frac{7}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B7%7D%7B4%7D)
Option C is correct.
3. The given equation is:
![\frac{3}{16}{\times}\frac{4}{21}](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B16%7D%7B%5Ctimes%7D%5Cfrac%7B4%7D%7B21%7D)
Multiplying both the terms, we get
=![\frac{1}{28}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B28%7D)
4. The given equation is:
![3\frac{8}{9}{\times}4\frac{4}{5}](https://tex.z-dn.net/?f=3%5Cfrac%7B8%7D%7B9%7D%7B%5Ctimes%7D4%5Cfrac%7B4%7D%7B5%7D)
Converting the improper fraction into the mixed fraction,
![\frac{35}{9}{\times}\frac{24}{5}](https://tex.z-dn.net/?f=%5Cfrac%7B35%7D%7B9%7D%7B%5Ctimes%7D%5Cfrac%7B24%7D%7B5%7D)
=![\frac{56}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B56%7D%7B3%7D)
5. One package contains=
pounds of raisins.
packages contains=
pounds of raisins.
=![\frac{14}{3}{\times}\frac{21}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B14%7D%7B3%7D%7B%5Ctimes%7D%5Cfrac%7B21%7D%7B4%7D)
=![\frac{49}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B49%7D%7B2%7D)
Therefore, the baker used
pounds of raisins.