The answers 5 because I looked it up
X=width of a coccer pitch
2x-20=length of a soccer pitch
Area (rectangule)=length x width
We suggest this equation:
x(2x-20)=6000
2x²-20x=6000
2x²-20x-6000=0
x²-10x-3000=0
We solve this quadratic equation:
x=[10⁺₋√(100-4*1*-3000)]/2=[10⁺₋√(100+12000)]/2=
=(10⁺₋110)/2
we have two solutions:
x₁=(10-110)/2=-50, invalid solution.
x₂=(10+110)/2=60
x=60
2x-20=2(60)-20=120-20=100
Solution: the length is 100 m, and the width is 60 m.
To check:
Area=100 m*60 m=6000 m²
The twice of width is =2(60 m)=120 m,
20 m less than twice its width is: 120 m-20 m=100 m=the length.
Answer: 117.5
Explanation: Assuming that after 10 years the lawn mower would have a value of 0. We can evenly divide $470 by the amount of years.
$750/10 = $75
We would then multiply 75*7.5 years to then realize the value lost over that amount of time would be $352.5, subtracting that from the original value of $470 would then be 117.5
1, both functions are linear
