Answer:
B. f(x) = -x^3 - x^2 + 7x - 4
Step-by-step explanation:
For this problem, we want to find the fastest-growing term in our given expressions and equate them when x is - infinite and when x is infinite to see the given trends.
For each of these equations, we will simply take the terms with the highest power and consider those. The two cases we need to consider is + infinite for x and - infinite for x. Let's check each of these equations.
Note, any value raised to an even power will be positive. Any negative value raised to an odd power will be negative.
<u>[A] - x^4</u>
<em>When x is +∞ --> - (∞)^4 --> f(x) is -∞</em>
<em>When x is -∞ --> - (-∞)^4 --> f(x) is -∞</em>
<em />
<u>[B] - x^3</u>
<em>When x is +∞ --> - (∞)^3 --> f(x) is -∞</em>
<em>When x is -∞ --> - (-∞)^3 --> f(x) is ∞</em>
<em />
<u>[C] 2x^5</u>
<em>When x is +∞ --> 2(∞)^5 --> f(x) is ∞</em>
<em>When x is -∞ --> 2(-∞)^5 --> f(x) is -∞</em>
<em />
<u>[D] x^4</u>
<em>When x is +∞ --> (∞)^4 --> f(x) is ∞</em>
<em>When x is -∞ --> (-∞)^4 --> f(x) is ∞</em>
<em />
Notice how only option B, when looking at asymptotic (fastest-growing) values, satisfies the originally given conditions for the relation of x to f(x).
Cheers.
Answer:
3000 bags
Step-by-step explanation:
In this case we must apply the formula of the mean, which would be the sum of the values divided by the amount of data is the mean:
m = (a1 + a2 ... an) / n
In this case we know the mean, we must know the 1987 data, therefore:
Let x be the number of bags sold in 1987, replacing in the previous equation:
2100 = (1800 + 1500 + x) / 3
2100 * 3 = 3300 + x
x = 6300 - 3300
x = 3000
Therefore, for the average to be a total of 2100 bags in those 3 years, the amount of bag sold in 1987 must have been 3000 bags
Answer:
180 minutes
Step-by-step explanation:
take 1,620 divide it by 9 and there is your answer
hope this helped
4/5 mile in 1/2 hour.
1/2 * 2 = 1
4/5 * 2 = 8/5
8/5 miles per hour or 1.6 miles per hour
