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kolezko [41]
3 years ago
12

A water tank has 800 liters of water and is going to be drained at a rate of 15 liters per minute.

Mathematics
1 answer:
Verdich [7]3 years ago
8 0
I think that’d be 53.3 till the water’s fully out.
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472 students are going on a field trip. 120 students will be returning home and the rest will be spending the night in cabins. a
Reil [10]

Step-by-step explanation:

472-120=352 sleep in a cabin

352÷8=44 cabins

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To make iced tea, 5 tea bags can be added to 1 gallon of water. Find how many bags can be used for 4 gallons of water
Nata [24]

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20 tea bags

Step-by-step explanation:

if 5 is 1 gallon then you do 5x4=20

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How many solutions does the equation 9x-3(x+8)=6x-24 have?
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3 years ago
My homework is due soon, help!!
Fantom [35]

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50.24

Step-by-step explanation:

A = Area

Radius = 4 (The radius is half of the diameter

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4 0
2 years ago
Walk fifty meters at 30o north or east from the old oak tree. (2) Turn 45o to your left (you should now be facing 75o north of e
saw5 [17]

Answer:

A straight line of approximately 75 meters, 1.4º north

Step-by-step explanation:

Hi, let's make it step by step to make it clearer

1) If we walk 50 meters in 30º angle Northeast, assuming the Old Oak tree is the point 0,0 and we're dealing with vectors in R^{2}. To say 30º Northeast is 30º clockwise (or 60º counter clockwise).

2) Then there was a the turning point to the left. If I turn to the left, on my compass 45º , I'll face 75º northeast.

3) Finally, the last vector leads to the treasure from the Old Oak Tree, i.e. the resultant.

So, let's calculate the norm which is the length of the each vector.

1) Graphing them we can find the points, then the components and then calculate the norm, the length of each vector.  

Since the Oak Tree is on (0,0). The turning point (50,86.61) and the Rock (R=(1.4,74,85) we can write the following vectors:

\vec{u}=\left \langle 50,86.61 \right \rangle\\\vec{v}=\left \langle -48.6,-11.76\right \rangle\\\vec{w}=\left \langle 1.4,74.85 \right \rangle

Now, let's calculate each vector length by calculating the norm.

\left \| \vec{u} \right \|=\sqrt{50^{2}+86.6^2}=100\\\left \| \vec{v} \right \|=\sqrt{(-48.6)^2+(-11.76)^2}=50\\\left \| \vec{u} \right \|=\sqrt{(1.4)^2+(74.85)^2}=74.86

The path is almost 75 meters. And since it is less than 15º degrees to the left of the North (or to the right) its direction is still north of the Old Oak Tree.

8 0
3 years ago
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