The HONC 1234 rule is a way to remember the bonding tendencies of hydrogen, oxygen, nitrogen, and carbon atoms in molecules. Hydrogen tends to form one bond, oxygen two, nitrogen three and carbon four.
It benefits of the solar radiation for out planet is that it gives us heat, natural sunlight and its pollution free.The disadvantage for solar radiation is that there are also some toxic materials and hazardous products used during the manufacturing process of solar photovoltaic systems, which can indirectly affect the environment.
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Here are some examples for those type of reactions.
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Combustion reaction: CH4(g) + 2 O2(g) --> CO2(g) + 2 H2O(l)
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Decomposition reaction: CaCO3(s) ---> CaO(s) + CO2(g)
</span><span>Double replacement: AgNO3(aq) + NaCl(aq) ---> AgCl(s) + NaNO3(aq)
</span>One common thing in all is that they are reactions. They have reactants to form new substances called product.
the compound with the smaller lattice energy is potassium sulphide here the size of the molecule play a important role
The quantity of energy released by the electrostatic attraction of oppositely charged ions is known as lattice energy (L.E). The ion's size and charge affect the lattice energy.
lattice energy is inversely proportional to size of ion and directly proportional to charge of the ion. They are each charged equally that is plus two and minus two However, because the Sulphur is larger in size and the oxygen is lesser in this case, The lattice energy of potassium oxide is larger the lattice energy of potassium sulphide is smaller.
To learn more about lattice energy :
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Answer:
0.50 M
Explanation:
Given data
- Mass of sodium sulfate (solute): 7.1 g
- Volume of solution: 100 mL
Step 1: Calculate the moles of the solute
The molar mass of sodium sulfate is 142.04 g/mol. The moles corresponding to 7.1 grams of sodium sulfate are:
![7.1g \times \frac{1mol}{142.02g} = 0.050mol](https://tex.z-dn.net/?f=7.1g%20%5Ctimes%20%5Cfrac%7B1mol%7D%7B142.02g%7D%20%3D%200.050mol)
Step 2: Convert the volume of solution to liters
We will use the relation 1 L = 1000 mL.
![100mL \times \frac{1L}{1000mL} =0.100L](https://tex.z-dn.net/?f=100mL%20%5Ctimes%20%5Cfrac%7B1L%7D%7B1000mL%7D%20%3D0.100L)
Step 3: Calculate the molarity of the solution
![M = \frac{moles\ of\ solute }{liters\ of\ solution} = \frac{0.050mol}{0.100L} =0.50 M](https://tex.z-dn.net/?f=M%20%3D%20%5Cfrac%7Bmoles%5C%20of%5C%20solute%20%7D%7Bliters%5C%20of%5C%20solution%7D%20%3D%20%5Cfrac%7B0.050mol%7D%7B0.100L%7D%20%3D0.50%20M)