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just olya [345]
3 years ago
11

You put two open cans of soda on the table. You took one can from the refrigerator and the other from your car. When you open th

em, which can of soda will lose the carbon dioxide more quickly and why?
the can from the refrigerator because there are more solute–solvent collisions
the can from the refrigerator because there are fewer solute–solvent collisions
the can from the car because there are more solute–solvent collisions
the can from the car because there are fewer solute–solvent collisions
Chemistry
2 answers:
Zina [86]3 years ago
7 0

Answer:  The can from the car because there are fewer solute–solvent collisions

Explanation: First of all; there is no such things as solute and solvent in aerated drinks because it is a colloid.

There will be dispersed phase which is known as to  be carbon dioxide and dispersion medium which is water in aerated drinks.

Now the can kept in the car will lose its fizz fastly enough in coparison to the one kept in refrigerator because the loss of carbon dioxide takes place fastly at higher temperatures.

irina [24]3 years ago
3 0
D. the can from the car because there are fewer solute-solvent collisions.
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If 43.1 g of O2 and 6.8 g of CO2 are placed in a 13.7 L container at 34 degrees C, what is the mixture of gasses?
jonny [76]

Answer:

The total pressure of the gas mixture = 2.76 atm

Note: The question is not complete. The complete question is as follow:

If 43.1 g of O2 and 6.8 g of CO2 are placed in a 13.7 L container at 34 degree Celsius , what is the pressure of the mixture of gases?

Explanation:

Mass of O₂ gas = 43.1 g, molar mass of O₂ gas = 32.0 g/mol

Number of moles of O₂ gas = 43.1/32.0 = 1.347 moles

Mass of CO₂ gas = 6.8 g, molar mass of CO₂ gas = 44.0 g

Number of moles of CO₂ gas = 6.8/44 = 0.155 moles

Total number of moles of gas mixture, n = (1.347 + 0.155) = 1.502 moles

Volume of gas mixture, V = 13.7 L

Temperature of gas mixture, T = 34 °C = (273.15 + 34) K = 307.15 K

Pressure of gas mixture = ?

Molar gas constant, R = 0.0821 liter·atm/mol·K.

Using the ideal gas equation: PV =nRT

P = nRT/V

P = (1.502 × 0.0821 × 307.15) / 13.7

P = 2.76 atm

Therefore, the total pressure of the gas mixture = 2.76 atm

5 0
3 years ago
You are given a sample of limestone, which is mostly CaCO3, to determine the mass percentage of Ca in the rock. You dissolve the
irakobra [83]

Answer:

34.15% is the mass percentage of calcium in the limestone.

Explanation:

Mass of precipitate that is calcium oxalate = 140.2 mg = 0.1402 g

1 mg = 0.001 g

Moles of calcium oxalate = \frac{0.1402 g}{128 g/mol}=0.001095 mol

1 mole of calcium oxalate have 1 mole of calcium atom.

Then 0.001095 moles of calcium oxalate will have 0.001095 moles of calcium atom.

Mass of 0.001095 moles of calcium :

0.001095 mol × 40 g/mol = 0.04381 g

Mass of sample of limestone = 128.3 mg = 0.1283 g

Percentage of calcium in limestone:

\frac{0.04381 g}{0.1283 g}\times 100=34.15\%

34.15% is the mass percentage of calcium in the limestone.

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3 years ago
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3 years ago
Determine the moles of NH3 that can form from 70.0 grams N2.
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Hey there!

5 moles will be produced.

N₂ has a molar mass of 28.014 g/mol.

Convert 70g to mol:

70 ÷ 28.014 = 2.5

In N₂ there are 2 nitrogen atoms. In NH₃ there is 1 nitrogen atom.

So, there will be twice as many moles of NH₃ because every one molecule of N₂ will produce two molecules of NH₃.

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