I did a few, to show you how.
Slide 1:
A) class A; range of 7
B) class a; 5.5
C) class b; 6.7 appx
D) class a
These are how to find each one:
Mean: add all the numbers and divide by the number of numbers. Ex. 1+2+3= 6/3=2
Median: middle of the numbers
Range: take the smallest value away from the largest value
IQR: find the median; find the range of the numbers above and below the median. Take the range of those two numbers that is the IQR
MAD: find the mean; take absolute value of numbers and subtract mean (|x|-mean); find sum of absolute value and difference; divide by the number of numbers.
Answer:
x = 5. I dont know if this is what your looking for but good luck.
Step-by-step explanation:
I got this question too and x = 5 was correct
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➷ Improper fractions are sometimes called 'top heavy fractions'
You'll see why below
Multiply 6 by 4:
6 x 4 = 24
Add 3 :
24 + 3 = 27
The improper fraction would be 27/4
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Answer:
Step-by-step explanation:
a) Frequency table:
Category Frequency
Dog 4
Cat 3
Fish 2
Hamster 1
b) Relative frequencies of each animal type
Dog: 4/10 = 0.4
Cat: 3/10 = 0.3
Fish: 2/10 = 0.2
Hamster: 1/10 = 0.1
c) Popularity
Dog is the most popular because it has the highest relative frequency.
Hamster is the least popular because it has the lowest relative frequency.
Answer:
The length of the unknown sides of the triangles are as follows:
CD = 10√2
AC = 10√2
BC = 10
AB = 10
ΔACD is a right angle triangle. Therefore, Pythagoras theorem can be used to find the sides of the triangle.
c² = a² + b²
where
c = hypotenuse side = AD = 20
a and b are the other 2 legs
lets use trigonometric ratio to find CD,
cos 45 = adjacent / hypotenuse
cos 45 = CD / 20
CD = 1 / √2 × 20
CD = 20 / √2 = 20√2 / 2 = 10√2
20² - (10√2)² = AC²
400 - 100(2) = AC²
AC² = 200
AC = √200 = 10√2
ΔABC is a right angle triangle too. Therefore,
AB² + BC² = AC²
Using trigonometric ratio,
cos 45 = BC / 10√2
BC = 10√2 × cos 45
BC = 10√2 × 1 / √2
BC = 10√2 / √2 = 10
(10√2)² - 10² = AB²
200 - 100 = AB²
AB² = 100
AB = 10
Step-by-step explanation: