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Blizzard [7]
3 years ago
9

Does the sum of the areas of the smaller Squares equal the area of the large squares

Mathematics
1 answer:
Keith_Richards [23]3 years ago
4 0
Not always. The side length matters. Bigger side lengths is bigger squares and smaller side length is smaller squares. So therefore the answer is no.
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Trigonometric ratios in right triangles pls help
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The answer is 4/3 if I am not mistaken
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4) A safe contains 120 coins, the value of which is $10. If the coins consist of nickels and dimes, how many of each kind are in
alexandr1967 [171]
There are 40 nickels and 80 dimes
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An Someone plz help me plz :(
zlopas [31]

Answer:

18

Step-by-step explanation:

original 3:4

now 18:24

Multiply by 6

6 0
3 years ago
20% of US High School teens vape. A local High School has implemented campaigns to reduce vaping among students and believes tha
zaharov [31]

Answer:

10.93% probability of observing 51 or fewer vapers in a random sample of 300

Step-by-step explanation:

I am going to use the normal approximation to the binomial to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

n = 300, p = 0.2

So

\mu = E(X) = np = 300*0.2 = 60

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{300*0.2*0.8} = 6.9282

What is the approximate probability of observing 51 or fewer vapers in a random sample of 300?

Using continuity corrections, this is P(X \leq 51 + 0.5) = P(X \leq 51.5), which is the pvalue of Z when X = 51.5 So

Z = \frac{X - \mu}{\sigma}

Z = \frac{51.5 - 60}{6.9282}

Z = -1.23

Z = -1.23 has a pvalue of 0.1093.

10.93% probability of observing 51 or fewer vapers in a random sample of 300

4 0
3 years ago
Simplify 8^4 •8^2 to an exponential expression
timurjin [86]

a^n\cdot a^m=a^{n+m}\\\\-------------------------------\\\\8^4\cdot8^2=8^{4+2}=8^6

5 0
3 years ago
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