I need to evaluate number 68.) and I need to know what sets of numbers to -1/3 belong to

Alebgra!!

Vikentia [17]

Answer:

I think it's 18

Step-by-step explanation:

P=2(l+w)=2(7+2)=18

it's been awhile I believe this is it

4 0

2 years ago

Read 2 more answers

Valerie runs track and field. At meets, Valerie lkes to buy protein bars, bananas and sports drinks Protein bars are $1. bananas

VladimirAG [237]

Complete Question

Valerie runs track and field. At meets, Valerie likes to buy protein bars, bananas, and sports drinks. Protein bars are $1, bananas are $0.50, and sports drinks are $2. Valerie has $10 to spend. She will spend no more than twice as much on sports drinks as bananas and at least three times as much on bananas as protein bars.

Let p represent the number of protein bars, b represent the number of bananas, and d represent the number of sports drinks that Valerie buys.

Which statements are true regarding Valerie's situation? Select all that apply A: p + 0.5b + 2d < 10 B: 0.5d + b + 3p < 10. C: d < 2b. D: b > 3p. E: 2d < b. F: 3b > p

Answer:

The statements that are true regarding Valerie's situation:

A: p + 0.5b + 2d < 10

C: d < 2b

D: b > 3p

Step-by-step explanation:

Lets represent

The number of protein bars as p.

The number of bananas as b.

The number of sports drinks that Valerie buys as d.

From the question:

We are told

Protein bars are $1

Bananas are $0.50

Sports drinks are $2.

She will spend no more than twice as much on sports drinks as bananas

d ≤ 2b = d < 2b

At least three times as much on bananas as protein bars.

b ≥ 3p = b > 3p

We are also told that:

Valerie has $10 to spend.

Hence:

$1 × p + $0.50 × b + $2 × d < $10

= p + 0.5b + 2d < 10

Therefore, the statements that are true regarding Valerie's situation:

A: p + 0.5b + 2d < 10

C: d < 2b

D: b > 3p

5 0

2 years ago

In a study of the accuracy of fast food drive-through orders, McDonald’s had 33 orders that were not accurate among 362 orders o

melomori [17]

Answer:

A. We need to conduct a hypothesis in order to test the claim that the true proportion of inaccurate orders p is 0.1.

B. Null hypothesis: $p=0.1$

Alternative hypothesis: $p \neq 0.1$

C. $z=\frac{0.0912 -0.1}{\sqrt{\frac{0.1(1-0.1)}{362}}}=-0.558$

D. $z_{\alpha/2}=-1.96$ $z_{1-\alpha/2}=1.96$

E. Fail to the reject the null hypothesis

F. So the p value obtained was a very high value and using the significance level given $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the true proportion of inaccurate orders is not significantly different from 0.1.

Step-by-step explanation:

Data given and notation

n=362 represent the random sample taken

X=33 represent the number of orders not accurate

$\hat p=\frac{33}{363}=0.0912$ estimated proportion of orders not accurate

$p_o=0.10$ is the value that we want to test

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

A: Write the claim as a mathematical statement involving the population proportion p

We need to conduct a hypothesis in order to test the claim that the true proportion of inaccurate orders p is 0.1.

B: State the null (H0) and alternative (H1) hypotheses

Null hypothesis: $p=0.1$

Alternative hypothesis: $p \neq 0.1$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

C: Find the test statistic

Since we have all the info required we can replace in formula (1) like this:

$z=\frac{0.0912 -0.1}{\sqrt{\frac{0.1(1-0.1)}{362}}}=-0.558$

D: Find the critical value(s)

Since is a bilateral test we have two critical values. We need to look on the normal standard distribution a quantile that accumulates 0.025 of the area on each tail. And for this case we have:

$z_{\alpha/2}=-1.96$ $z_{1-\alpha/2}=1.96$

P value

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a bilateral test the p value would be:

$p_v =2*P(z$

E: Would you Reject or Fail to Reject the null (H0) hypothesis.

Fail to the reject the null hypothesis

F: Write the conclusion of the test.

So the p value obtained was a very high value and using the significance level given $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the true proportion of inaccurate orders is not significantly different from 0.1.

6 0

3 years ago

Adele has 3 64-ounce cartons of orange juice and 3 48-ounce cans of apple juice. How much juice does she have altogether?

Readme [11.4K]

She has 6 ounce of cans

7 0

3 years ago

What is 6(x+3)=2(2x+5)

koban [17]

Answer:

x = -4 ;

Step-by-step explanation:

6(x+3)=2(2x+5)

Distribution

6x+18 = 4x + 10

Subtract 4x on both sides

2x+18 = 10

Subtract 18 on both sides

2x = -8

Divided by 2

x = -4

Now if we have to substitute the value of X

6(-4+3)=2(-8+5)

Parenthesis first

6(-1) = 2(-3)

-6 = -6

7 0

3 years ago