Find the measure of a dilated image of segment CD, 5 units long, with a scale factor of 4?

Mathematics

1 answer:

Amiraneli [1.4K]3 years ago

8 0

The measure would be 20 since five times four is 20

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For an arithmetic sequence, a35=57. If the common difference is 5. Find a1 and the sum of the first 61 terms.

Flauer [41]

$\displaystyle\bf\\a_{35}=57\\r=5\\----\\a_1=?\\S_{61}=?\\----\\Solve:\\1)\\a_1=a_{35}-(35-1)\times r=57-34\times 5=57-170=-113\\\boxed{\bf a_1=-113}\\\\$

$\displaystyle\bf\\2)\\A_{61}=a_1+(61-1)\times r=-113+60\times5=-113+300=187\\\\S_{61}=(-113)+(-108)+(-103)+...+(-8)+(-3)+2+7+12+...+187\\\\S_{61}=SA+SB\\\\SA=(-113)+(-108)+(-103)+...+(-8)+(-3)=-(3+8+103+108+113)\\\\n=\frac{113-8}{5}+1=\frac{105}{5}+1=21+1=22~terms\\SA=-\Big( \frac{n(113+3)}{2} \Big)=-\Big( \frac{22\times116}{2} \Big)=-11\times116 =-1276$

$\displaystyle\bf\\SB=2+7+12+...+187\\\\n=\frac{187-2}{5}+1=\frac{185}{5}+1=37+1=38~terms\\\\SB=\frac{n(187+2)}{2}=\frac{38\times189}{2}=19\times189=3591\\\\S_{61}=SA+SB=-1276+3591=2315\\\\\boxed{\bf S_{61}=2315}$

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What is the product of 4xy and y2 + 2x?

juin [17]

The product of 4xy and y² + 2x can also be written as
4xy(y² + 2x)

When we have brackets like this, we multiply whatever is left of the brackets by everything inside.

1) 4xy multiplied by y²
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2) 4xy multiplied by 2x
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3) Add together 4xy³ and 8x²y
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You can keep reducing until both sides of the fraction can't be divided by the same number anymore.

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Firdavs [7]

<span>The answer should be (12x + 20) (2x + 5)</span>

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