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Scorpion4ik [409]
3 years ago
15

Find the measure of a dilated image of segment CD, 5 units long, with a scale factor of 4?

Mathematics
1 answer:
Amiraneli [1.4K]3 years ago
8 0
The measure would be 20 since five times four is 20
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Write an equation that expresses the following relationship. p varies jointly with the square of d and the cube of u In your equ
Veronika [31]

Answer:

p= kd^{2}u^{3}

Step-by-step explanation:

Using k as the constant of proportionality.

The expression that expresses the relationship : p varies jointly with the square of d and the cube of u.

Varies jointly means that p will change as 'd' and 'u' will change together with respect to their powers.

We get the expression as:

p= kd^{2}u^{3}

5 0
4 years ago
What is the value of X?
andrezito [222]

Solution:

<u>Note that:</u>

  • 3x + 50 = 6x - 10 (Vertically opposite angles)

Simplify the equation to find x.

<u>Add 10 both sides.</u>

  • 3x + 50 = 6x - 10
  • => 3x + 50 + 10 = 6x - 10 + 10
  • => 3x + 60 = 6x

<u>Subtract 3x both sides.</u>

  • 3x + 60 = 6x
  • => 3x - 3x + 60 = 6x - 3x
  • => 60 = 3x

<u>Divide 3 both sides.</u>

  • 60 = 3x
  • => 60/3 = 3x/3
  • => x = 20
6 0
3 years ago
Read 2 more answers
A rectangular garden has side lengths of 12 feet and (x+10) feet. The garden has an area of 480 square feet. Write an equation a
Eddi Din [679]

Answer:

Step-by-step explanation:

12+x+10=480

22+x=480

x=458

2(12)+2(x+10)=480

24+2x+20=480

44+2x=480

2x=436

x=218

7 0
3 years ago
what is the growth factor of y=34×4^x, the initial amount of y=15×3^x and the decay factor of y=17×0.2^x
11Alexandr11 [23.1K]
So the growth factor is the base of the exponential term, so the base of y = 34 * 4^x is 4.
the initial amount is the amount at x = 0
y = 15 * 3^xy = 15 * 3^0y = 15 * 1y = 15 is the initial amount
the decay factor of y=17×0.2^x is same as the growth factor, it is 0.2
5 0
3 years ago
Which of the following types of information is best suited for display on a double line graph?
sammy [17]
A.) average wages paid to men and women over 5 years
4 0
4 years ago
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