Let A be the speed of hiker A and B the speed of hiker B.
let's say that B is faster than A, so B=A+0.5
we know that they met after 2 hours, and the distance each walked after 2 hours is given by:
One of the hikers travels at 4 miles per hour, the other one at 4.5 miles per hour
Definitely would have to be a rhombus
Answer:
The rhombus ABCD has an area of 22 square units.
Step-by-step explanation:
The coordinates of rhombus ABCD are shown in the image attached below. The area of the rhombus can be found in terms of their diagonals, which are now calculated by Pythagorean Theorem:
![AC = \sqrt{[6-(-4)]^{2}+[8-(-4)]^{2}}](https://tex.z-dn.net/?f=AC%20%3D%20%5Csqrt%7B%5B6-%28-4%29%5D%5E%7B2%7D%2B%5B8-%28-4%29%5D%5E%7B2%7D%7D)
![BD = \sqrt{(4-6)^{2}+[0-(-2)]^{2}}](https://tex.z-dn.net/?f=BD%20%3D%20%5Csqrt%7B%284-6%29%5E%7B2%7D%2B%5B0-%28-2%29%5D%5E%7B2%7D%7D)
The area of the rhombus is: ( and )
The rhombus ABCD has an area of 22 square units.
The percentage increase in the student's height is 10.52%.
Here we are given that a student's height increases from 1.52m to 1.68m.
Thus, the absolute increase in the student's height will be-
1.68 - 1.52 = 0.16 meters.
Now, we need to find the percentage increase in the student's height.
The formula for calculating percentage increase is given by-
Percentage increase = change in value/ initial value * 100
Here, the change in value is 0.16 meters and the initial value is 1.52 meters.
Thus, percentage increase in height = 0.16 / 1.52 *100
= 1600/ 152
= 400/ 38
= 200/ 19
= 10.52%
Thus, the increase in the student's height is 10.52%.
Learn more about percentage change here-
https://brainly.in/question/19592355
#SPJ9
Fraction: 2/3
Decimal: .33 (for middle schoolers I suppose)
Percent: 33% (Please Learn you math)
I hope this helped you
