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umka21 [38]
3 years ago
13

What is the awser plz help and dont just awser because u want points plz

Mathematics
1 answer:
11111nata11111 [884]3 years ago
7 0

Answer:

I think it's C because it's the only one that is different. I could be wrong though

Step-by-step explanation:

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Does anyone know how to do this???
Vera_Pavlovna [14]

Answer:

yes

Step-by-step explanation:

you must first see what spinners says then you follow what spinners says

6 0
3 years ago
PLEASE PLEASE HELP ME 30 POINTS!<br><br> x + 20 ≤ -10
Artemon [7]

X + 20 <= -10

Subtract 20 from both sides:

X <= -30

7 0
3 years ago
Read 2 more answers
The number of major earthquakes in a year is approximately normally distributed with a mean of 20.8 and a standard deviation of
SCORPION-xisa [38]

Answer:

a) 51.60% probability that in a given year there will be less than 21 earthquakes.

b) 49.35% probability that in a given year there will be between 18 and 23 earthquakes.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 20.8, \sigma = 4.5

a) Find the probability that in a given year there will be less than 21 earthquakes.

This is the pvalue of Z when X = 21. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{21 - 20.8}{4.5}

Z = 0.04

Z = 0.04 has a pvalue of 0.5160.

So there is a 51.60% probability that in a given year there will be less than 21 earthquakes.

b) Find the probability that in a given year there will be between 18 and 23 earthquakes.

This is the pvalue of Z when X = 23 subtracted by the pvalue of Z when X = 18. So:

X = 23

Z = \frac{X - \mu}{\sigma}

Z = \frac{23 - 20.8}{4.5}

Z = 0.71

Z = 0.71 has a pvalue of 0.7611

X = 18

Z = \frac{X - \mu}{\sigma}

Z = \frac{18 - 20.8}{4.5}

Z = -0.62

Z = -0.62 has a pvalue of 0.2676

So there is a 0.7611 - 0.2676 = 0.4935 = 49.35% probability that in a given year there will be between 18 and 23 earthquakes.

5 0
3 years ago
1/ 99 to 4 significant figures​
musickatia [10]

Answer:

  0.01010

Step-by-step explanation:

The decimal equivalent is ...

  \dfrac{1}{99}=0.\overline{01}

Rounded to 4 significant figures, it is ...

  0.01010

4 0
2 years ago
(Please help ill give brainliest)
elena-s [515]

Answer:

80 answer is 80

Step-by-step explanation:

50+30 = 80 answer

6 0
2 years ago
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