Answer:
Step-by-step explanation:
The volume of the pyramid = (1/3)*area of base *height
= (1/3)*10*24*13 = 1040 cubic units.
The total surface area = area of rectangular base + area of 2 isosceles triangles with a base of 24 units + area of 2 isosceles triangles with a base of 10 units.
Area of rectangular base = 24*10 = 240 sq units.
The slant height of isosceles triangles with a base of 24 units = [(10/2)^2+13^2]^0.5 = [25+169]^0.5 = 194^0.5 = 13.92838828 units.
The area of 2 isosceles triangles with a base of 24 units 2*24*13.92838828/2 = 334.2813187 sq units.
The slant height of isosceles triangles with a base of 10 units = [(24/2)^2+13^2]^0.5 = [144+169]^0.5 = 194^0.5 = 17.69180601 units.
The area of 2 isosceles triangles with a base of 10 units 2*10*17.69180601/2 = 176.9180601 sq units.
The total surface area of the pyramid = 240 + 334.2813187 + 176.9180601 = 591.9731247 sq units.
You need to distribute the 3, so your answer would be 6b-3
Answer:
c
Step-by-step explanation:
