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DochEvi [55]
3 years ago
11

Which sequence could be partially defined by the recursive formula f (n + 1) = f(n) + 2.5 for n ≥ 1?

Mathematics
2 answers:
Anna007 [38]3 years ago
8 0
<h2>Answer:</h2>

The sequence that could be partially defined by the given recursive formula is:

           -10, -7.5 , -5 , -2.5 ,........

<h2>Step-by-step explanation:</h2>

We are given a recursive formula as:

                  f(n+1)=f(n)+2.5 for n≥1

Hence, from the given options we will check the difference of which sequence is: 2.5

A)

   2.5, 6.25, 15.625, 39.0625, …

6.25-2.5=3.75

15.625-6.25=9.375

As we could see that the common difference is not 2.5

Hence, option: A is incorrect.

B)

        2.5, 5, 10, 20

5-2.5=2.5

10-5=5

20-10=10

As the common difference is not 2.5.

Hence, option: B is incorrect.

C)

               –10, –7.5, –5, –2.5, …

-7.5-(-10)=-7.5+10=2.5

-5-(-7.5)=5+7.5=2.5

and -2.5-(-5)=-2.5+5=2.5

As the common difference is 2.5.

           Hence, option: C is correct.

D)

     -10, -25 , 6.25 , 156.25

-25-(-10)=-25+10= -15

As the common difference is not 2.5

Hence, option: D is incorrect.

Stells [14]3 years ago
3 0
<span>–10, –7.5, –5, –2.5, …

Is defined by the formula because the next term can be obtained by adding 2.5 to the current one.</span>
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#
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4. The point Z is the orthocenter of the triangle.

5. The length of GZ is of 9 units.

6. The length of OT is of 9.6 units.

<h3>What is the orthocenter of a triangle?</h3>

The orthocenter of a triangle is the point of intersection of the three altitude lines of the triangle.

Hence, from the triangle given in the end of the answer, point Z is the orthocenter of the triangle.

For the midpoints connected through the orthocenter, the orthocenter is the midpoint of these segments, hence:

  • The length of segment GZ is obtained as follows: GZ = 0.5 GU = 9 units. -> As z is the midpoint of the segment.
  • The length of segment OT is obtained as follows: OT = 2ZT = 2 x 4.8 = 9.6 units.

<h3>Missing Information</h3>

The complete problem is given by the image at the end of the answer.

More can be learned about the orthocenter of a triangle at brainly.com/question/1597286

#SPJ1

8 0
1 year ago
If the function h is defined by h(x)=<img src="https://tex.z-dn.net/?f=x%5E%7B2%7D" id="TexFormula1" title="x^{2}" alt="x^{2}" a
harkovskaia [24]

Given:

The function is:

h(x)=x^2-3x+5

To find:

The value of h(2x+1).

Solution:

We have,

h(x)=x^2-3x+5

Putting x=2x+1, we get

h(2x+1)=(2x+1)^2-3(2x+1)+5

h(2x+1)=(2x)^2+2(2x)(1)+(1)^2-3(2x)-3(1)+5

h(2x+1)=4x^2+4x+1-6x-3+5

On combining like terms, we get

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h(2x+1)=4x^2-2x+3

Therefore, the required function is h(2x+1)=4x^2-2x+3.

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