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frosja888 [35]
4 years ago
15

Help plz. I'll mark brainliest

Mathematics
1 answer:
abruzzese [7]4 years ago
6 0
I answered this question just now! Did you add another question like this?

1. rule = r - 12 (number = 25)
2. rule = a + 34 (number = 43) 
3. rule = s - 5 (number = 20)
4. rule = b + 16 (number = 32)
5. rule = w + 3 (number = 9)
6. rule = n + 9 (number = 42)

7. 15 - n when n = 9 would be 15 - 9, and your answer would be 6.

8. "32 more than a number d" implies add d to 32, so your answer is C. 32 + d
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If a kid is 145 cm and he owns an eraser that is 6.8 cm long, 1.5 cm wide, and 1.5 cm tall. If a scientist shoots him with an en
never [62]
To answer this you’d have to use an 2 step equation 145x= 1000
When u get the answer for x multiply the answer by the erasers original area to find the area of the eraser it would be lengthtimes width times height
4 0
4 years ago
How do I find the slope of the line containing the two points (9,0) and (-5,6)
deff fn [24]
  • Slope Formula: \frac{y_2-y_1}{x_2-x_1}

So using the slope formula, plug in the two points and solve for it as such:

\frac{0-6}{9-(-5)}=-\frac{6}{14}\div \frac{2}{2}=-\frac{3}{7}

<u>The slope is -3/7.</u>

7 0
4 years ago
Circle O and circle P are congruent. Given that arc AB is congruent to arc DE, what can you conclude from the diagram?
wlad13 [49]

Answer:

Central angle is equal in both circles

And the two triangles inscribed in circle is congruent.

Step-by-step explanation:

We have been given the two circles which are congruent O and P.

Ab is congruent to DE

So, the central angle of two circles will be equal circles being congruent.

And the two triangles AOB and EPD are congruent

Radius of the congruent circle is equal

Hence, OB=PD

             AB=DE

And ∠BOA=∠DPE

By SAS property ΔAOB ≅ΔEPD


5 0
4 years ago
Write an equation for the translation of "left 7 units<br><br> Y=|x|
ss7ja [257]

i need the answer to this lol

8 0
3 years ago
Civil an airport, a factory, and a shopping center are at the vertices of a right triangle formed by three highways. the airport
vekshin1

Answer:

<em>The shortest possible length for the service road is 2.88 miles.</em>

Step-by-step explanation:

According to the below diagram, A, B and C are the positions of airport, shopping center and factory respectively.

Given that,  AB= 3.6 miles, BC= 4.8 miles and AC= 6.0 miles

In right triangle ABC

tan(\angle ACB)=\frac{AB}{BC} \\ \\ tan(\angle ACB)= \frac{3.6}{4.8}=0.75\\ \\ \angle ACB= tan^-^1(0.75)=36.8698.... degree

The shortest possible length for the service road from the shopping center to the highway that connects the airport and factory is BD.

That means, \triangle BCD is also a right triangle in which \angle BDC=90\°, Hypotenuse(BC)= 4.8 miles and BD is the opposite side in respect of \angle DCB or \angle ACB.

Now in right triangle BCD

Sin(\angle ACB)=\frac{BD}{BC}\\ \\ Sin(36.8698...)=\frac{BD}{4.8}\\ \\ BD=4.8*Sin(36.8698...)=2.88

So, the shortest possible length for the service road is 2.88 miles.

4 0
4 years ago
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