Help, and I just reviewed this screenshot too So it's NOT BLURRRY, if you have anything to say, pls just say it under the "ask a
bout question" part
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Answer:
Height of second tower = 17.32m
Step-by-step explanation:
I have attached a diagram depicting the question.
From the diagram, The first tower is depicted by side AEB and the second tower CD.
While d is the distance that separates the two towers and it's given as 15m.
Now, since the angle of depression of the second tower’s base is 60°, then for triangle BAC. Angle C = 60°.
Thus; using trigonometric ratios;
tan 60° = AB/AC.
This gives; AB = d*tan 60°
Similarly, for the triangle BED, BE = d*tan 30°
Since, AE = CD, thus ;
CD = AB − BE
CD = d (tan 60° − tan 30°)
CD = 15(1.7321 − 0.5774)
CD = 15 × 1.1547
CD ≈ 17.32 m.
So, height of second tower = 17.32 m
Step-by-step explanation:
draw the net
there are 3 squares, each with a L = 5m and W = 1.5 +1.5m
2 triangles with a base of 1.5 + 1.5 and a height of 2.6m
Area of a rectangle = L x W
" " Triangle = 0.5 x b x h
so youd write and solve 3 rectangles x ( 5 m x 1.5 + 1.5) + 2 triangles x (0.5 x (1.5 +1.5) x 2.6m)
also look up the equation for surface area for this shape. Should give you the same thing. This method makes it more intuitive
