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Andrei [34K]
3 years ago
6

The area of rectangle A is 11/12 square meters.The area of rectangle B is 8/12 square meters.How much larger is rectangle A?

Mathematics
1 answer:
mixer [17]3 years ago
5 0
Answer:
Rectangle A is 1/4 m² larger than rectangle B

Explanation:
We are given that:
Area of triangle A = 11/12 m²
Area of rectangle B = 8/12 m²

To know how much larger is rectangle A than rectangle B, all we have to do is subtract the area of rectangle B from rectangle A as follows:
Difference in area = 11/12 - 8/12 = 3/12 = 1/4 m²

This means that rectangle A is 1/4 m² larger than rectangle B.

Hope this helps :)
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Step-by-step explanation:

If 2 pound serves 8 people you can express that as a ratio of 2:8 so to get 8 people to 40 you multiply by 5 so you must do the same for the amount of pasta so 2 multiplied  5 equals 10.  

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Solve 5x – 2y = 11 for y.​
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42

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3 years ago
From a thin piece of cardboard 30 in. by 30 in., square corners are cut out so that the sides can be folded up to make a box. Wh
Brilliant_brown [7]

Answer:

Dimensions 5in x 10in x 10in will yeild a box with a max. volume of  500 cubic inches

Step-by-step explanation:

Volume =  height x length x width

considering 'x' as the length of the square corners that has been cut out from the cardboard and also, that is height of the cardboard box.

square corners are cut out so that the sides can be folded up to make a box, cardboard sides would reduce by 2x

therefore,

V = x  (30-2x) (30-2x) ---> eq(1)

V=( 30x - 2x²) (30-2x)

V= 900x- 60x² - 60x² + 4x³

V=  4x³ - 120 x²+ 900x

Taking derivative w.r.t 'x'

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dV/dx = 4 (3x² - 60x +225)

For maximum dV/dx, make it equal zero

dV/dx = 0

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3x² - 60x+225=0   (taking 3 common)

x² - 20x + 75 =0

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V= 500 cubic inches,

Therefore, Dimensions 5in x 10in x 10in will yeild a box with a max. volume of  500 cubic inches

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4 years ago
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