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NemiM [27]
3 years ago
12

Please help solve |-6y+3|=4|y-2|

Mathematics
1 answer:
nekit [7.7K]3 years ago
8 0

Answer:

6

y

+

3

=

−

4

y

2

Move  

4

y

2

to the left side of the equation by adding it to both sides.

6

y

+

3

+

4

y

2

=

0

Use the quadratic formula to find the solutions.

−

b

±

√

b

2

−

4

(

a

c

)

2

a

Substitute the values  

a

=

4

,  

b

=

6

, and  

c

=

3

into the quadratic formula and solve for  

y

.

−

6

±

√

6

2

−

4

⋅

(

4

⋅

3

)

2

⋅

4

Simplify.

Tap for more steps...

y

=

−

3

±

i

√

3

4


Step-by-step explanation:


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Step-by-step explanation:

This is just -3 * 3

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Answer:

10,000 :)

Step-by-step explanation:

5,089 rounded =5,000

4,722 rounded= 5,000

=  10,000

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Step-by-step explanation:

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2 years ago
Several years​ ago, 38​% of parents who had children in grades​ K-12 were satisfied with the quality of education the students r
Colt1911 [192]

Answer:

0.428 - 1.96\sqrt{\frac{0.428(1-0.428)}{1165}}=0.3995

0.428 + 1.96\sqrt{\frac{0.428(1-0.428)}{1165}}=0.4564

We are confident that the true proportion of people satisfied with the quality of education the students receive is between (0.3995, 0.4564), since the lower value for this confidence level is higher than 0.38 we have enough evidence to conclude that the parents' attitudes toward the quality of education have changed.

Step-by-step explanation:

For this case we are interesting in the parameter of the true proportion of people satisfied with the quality of education the students receive

The confidence level is given 95%, the significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical values are:

z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96

The estimated proportion of people satisfied with the quality of education the students receive is given by:

\hat p =\frac{499}{1165}= 0.428

The confidence interval for the proportion if interest is given by the following formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

And replacing the info given we got:

0.428 - 1.96\sqrt{\frac{0.428(1-0.428)}{1165}}=0.3995

0.428 + 1.96\sqrt{\frac{0.428(1-0.428)}{1165}}=0.4564

We are confident that the true proportion of people satisfied with the quality of education the students receive is between (0.3995, 0.4564), since the lower value for this confidence level is higher than 0.38 we have enough evidence to conclude that the parents' attitudes toward the quality of education have changed.

8 0
3 years ago
I need help PLEASE!!!
Stella [2.4K]

9514 1404 393

Answer:

  y = -4/3x +23/2

Step-by-step explanation:

The tangent of interest is perpendicular to the radius at the given point on the circle. To find the perpendicular, it helps to know the slope of the radius segment. To find that, we need the center of the circle.

The center of the circle can be found by completing the square for each variable.

  (x^2 -2x) +(y^2 +4y) = 20

  (x^2 -2x +1) +(y^2 +4y +4) = 20 +1 +4

  (x -1)^2 +(y +2)^2 = 25

Comparing this equation to the standard form equation for a circle, we can find the center.

  (x -h)^2 +(y -k)^2 = r^2 . . . . . . . circle of radius r centered at (h, k)

The center of circle P is (1, -2).

__

The slope m' of the line segment between (1, -2) and (5, 1) is given by ...

  m' = (y2 -y1)/(x2 -x1)

  m' = (1 -(-2))/(5 -1) = 3/4

The slope m of the perpendicular line is the opposite reciprocal of this, so is ...

  m = -1/m' = -1/(3/4) = -4/3

The y-intercept of the desired line can be found from ...

  b = y -mx . . . . . . . for m=-4/3 and (x, y) = (5, 1)

  b = 1 -(-4/3)(5) = 23/3

Then the equation of tangent line AB is ...

  y = mx +b

  y = -4/3x +23/3

6 0
2 years ago
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