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4 years ago

I need help with these my teacher didn’t teach us this

Mathematics

1 answer:

kolezko [41]4 years ago

6 0

Answer:

Step-by-step explanation:

I am very sorry if this doesnt make sense but i tried to give you an example for the first one so you could figure out the 4 and 5.

If y=12 when x=6, determine y when x=18.

Ok if y=12 and x=6 they add up to 18. So X=6 then you are going to have to times 6 by three to get x to equal 18. That means we have to times y by 3 also which equals 36. We can check this by making sure they are congruent or the same. So if the origanal question said y equals 12 and x equals 6. How do you make sure it's the right answer? What do they have in commmon? Well to get 12 you have to multiply 6 by 2 to get 12. And to get 6 you have to divide 12 by 2. So the common number is 2. So for x to equal 18 we have to figure out is the have something in common, so 18 times 3 equals 36 and if 36 divided by 3 we get 18. So the common number is 3.

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erik [133]

Answer:

The solutions of the system of equations are the points

$(\frac{1-\sqrt{33}} {2},\frac{5-\sqrt{33}} {2})$

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Step-by-step explanation:

we have

$y=-x^{2} +2x+10$ ----> equation A

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in this problem we have

$-x^{2} +x+8=0$

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$x=\frac{-1+\sqrt{33}} {-2}$ -----> $x=\frac{1-\sqrt{33}} {2}$

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$y=\frac{1-\sqrt{33}} {2}+2$ ----> $y=\frac{5-\sqrt{33}} {2}$

For $x=\frac{1+\sqrt{33}} {2}$

$y=x+2$

$y=\frac{1+\sqrt{33}} {2}+2$ ----> $y=\frac{5+\sqrt{33}} {2}$

therefore

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$(\frac{1-\sqrt{33}} {2},\frac{5-\sqrt{33}} {2})$

$(\frac{1+\sqrt{33}} {2},\frac{5+\sqrt{33}} {2})$

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