Answer:
missing measure is 32
Step-by-step explanation:
Answer:
and
Step-by-step explanation:
Given
Required
Solve for x and y
Make x the subject in the second equation
Substitute 31 - 5y for x in
Collect like terms
Solve for y
Substitute 6 for y in
Answer:
(3/8) + (1/8)cos 4x - (1/2)cos 2x
Step-by-step explanation:
sin^(4) x = (sin² x ) (sin² x) ------ (1)
Recall double angle identity: cos 2x = 1 - 2 sin² x
or sin² x = (1/2) (1 - cos 2x)
substituting this into (1)
sin^(4) x = (sin² x ) (sin² x) = [ (1/2)(1-cos 2x) ]²
= (1/4) ( 1 - 2 cos 2x + cos²2x) ------(2)
Also recall double angle identiy : cos 2x = 2 cos² x - 1
or cos² x = (1/2) ( 1+ cos 2x)
or cos² 2x = (1/2) ( 1+ cos 4x)
substituting this into (2)
(1/4) ( 1 - 2 cos 2x + cos²2x)
= (1/4) [ 1 - 2 cos 2x + (1/2)(1 + cos 4x) ] (expand and reduce)
= (3/8) + (1/8)cos 4x - (1/2)cos 2x
X - 9 = 15
-9 = 15 - x
-9 - 15 = - x
-24 = -x
x = 24
Answer:
∑ₙ₌₁⁸ (3n − 9)
Step-by-step explanation:
This is an arithmetic series where the first term is -6 and the common difference is 3. The nth term can be written as:
aₙ = a₁ + d (n − 1)
aₙ = -6 + 3 (n − 1)
There are 8 terms in this series, so the sum is:
∑ₙ₌₁⁸ [-6 + 3 (n − 1)]
Simplified:
∑ₙ₌₁⁸ (3n − 9)