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3 years ago

I need help ASAP PLEASE ASAP!!!

Mathematics

2 answers:

ArbitrLikvidat [17]3 years ago

6 0

The area is 10:) good luck on it

zysi [14]3 years ago

3 0

The area is 10 just use a area calculator!

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SHOW YOUR FORMULA AND SOLUTION

spayn [35]

Answer:

2500 kg

Step-by-step explanation:

Given:

• Force produced by the truck = F = 15,000 Newtons Acceleration of the truck = a = 6 m/s²

To find:

Mass of the truck if force is 15000 newtons and acceleration is 6 m/s²

Formula:

Force = Mass Acceleration

Substituting the above values:

15000N Mass×6

Mass = 15,000/6

Mass = 2500 kg

7 0

1 year ago

The probability of choosing a rotten apple from the bag of apples is Four-fifths. Which term best describes this probability? im

agasfer [191]

I think the answer is likely

5 0

3 years ago

Read 2 more answers

The half-life of a radioactive substance is the time it takes for a quantity of the substance to decay to half of the initial am

posledela

Step-by-step walkthrough:

Well a standard half-life equation looks like this.

$N = N_0 * (\frac{1}{2})^{t/p$

$N_0$ is the starting amount of parent element.

$N$ is the end amount of parent element

$t$ is the time elapsed

$p$ is a half-life decay period

We know that the starting amount is 74g, and the period for a half-life is 2.8 days.

Therefore you can create a function based off of the original equation, just sub in the values you already know.

$N(t) = 74g * (\frac{1}{2})^{t/2.8days$

This is easy now that we have already made the function. Here we just reuse it, but plug in 2.8 days.

$N(t) = 74g * (\frac{1}{2})^{t/2.8days} = N(2.8days) = 74g * (\frac{1}{2})^{2.8days/2.8days}\\= 74g * \frac{1}{2} = 37g$

Now we just gotta do some algebra. Use the original function but this time, replace $N(t)$ with 10g and solve algebraically.

$10g = 74g * (\frac{1}{2})^{t/2.8days}\\\\\frac{10g}{74g} = (\frac{1}{2})^{t/2.8days}$

Take the log of both sides.

$log(\frac{5}{37}) = log((\frac{1}{2})^{t/2.8days})$

Use the exponent rule for log laws that, $log(b^x) = x*log(b)$

$log(\frac{5}{37}) = \frac{t}{2.8days} * log(\frac{1}{2})$

$\frac{log(\frac{5}{37})}{log(\frac{1}{2})} = \frac{t}{2.8days}$

$2.8 * \frac{log(\frac{5}{37})}{log(\frac{1}{2})} = t$

slap that in your calculator and you get

$t = 8.1 days$

7 0

2 years ago

Item 19 A surveyor holds a laser range finder 3 feet above the ground and determines that the range finder is 112 feet from a bu

liberstina [14]

The building is about 70.95 feet tall.

The building and the laser range will form a right triangle. You can use the Pythagorean Theorem to find the height of the building.

112^2 + b^2 = 131^2
b = 67.95

However, don't forget to add on 3 because that is the height of the laser range.

8 0

3 years ago

What is the volume

icang [17]

Answer:67,200

Step-by-step explanation: You multiply length×width×height.

Sorry If I am Wrong.

7 0

3 years ago