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givi [52]
3 years ago
14

Please Answer Quick 70 Points !

Mathematics
1 answer:
Kipish [7]3 years ago
6 0

Answer:

The ordered pair (7, 19) is a solution to the first equation because it makes the first equation true

The ordered pair (7, 19) is not a solution to the system because it makes at least one of the equations false

Step-by-step explanation:

we have

2x-y=-5 -----> First equation

x+3y=22 -----> Second equation

Solve the system of equations by graphing

Remember that the solution of the system is the intersection point both graphs

The solution is the point (1,7)

The ordered pair (7,19) lie on the first line, so is a solution of the first equation

see the attached figure

<u><em>Verify each statement</em></u>

case 1) The ordered pair (7, 19) is a solution to the first equation because it makes the first equation true

The statement is true

case 2) The ordered pair (7, 19) is a solution to the second equation because it makes the second equation true

The statement is false, because the ordered pair (7,19) not lie on the second line

case 3) The ordered pair (7, 19) is not a solution to the system because it makes at least one of the equations false

The statement is true

case 4) The ordered pair (7, 19) is a solution to the system because it makes both equations true

The statement is false,because it makes only the first equation true

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If the circle below is cut from the square of plywood below, how many square inches of plywood would be left over? Use π = 3.14,
Elis [28]

Answer:

86in²

Step-by-step explanation:

Find the complete question attached

Area of the circle = πr²

Area of the square = L²

Length of the side of the square

r is the radius of the circle

r = L/2 = 20/2 =10in

Given

Length of the side of the circle = 20in

Area of the square = 20²

Area of the square = 400in²

Area of the circle =π(10)²

Area of the circle = 3.14(100)

Area of the circle= 314in²

Amount of plywood left over = 400in²-314in² = 86in²

8 0
3 years ago
1. The mechanics at Lincoln Automotive are reborning a 6 in deep cylinder to fit a new piston. The machine they are using increa
Firdavs [7]

Answer:

0.0239\frac{in^{3}}{min}

Step-by-step explanation:

In order to solve this problem, we must start by drawing a diagram of the cylinder. (See attached picture)

This diagram will help us visualize the problem better.

So we start by determining what data we already know:

Height=6in

Diameter=3.8in

Radius = 1.9 in (because the radius is half the length of the diameter)

The problem also states that the radius will increase on thousandth of an inch every 3 minutes. We can find the velocity at which the radius is increasing with this data:

r'=\frac{1/1000in}{3min}

which yields:

r'=\frac{1}{3000}\frac{in}{min}

with this information we can start solving the problem.

First, the problem wants us to know how fast the volume is increasing, so in order to find that we need to start with the volume formula for a cylinder, which is:

V=\pi r^{2}h

where V is the volumen, r is the radius, h is the height and π is a mathematical constant equal approximately to 3.1416.

Now, the height of the cylinder will not change at any time during the reborning, so we can directly substitute the provided height, so we get:

V=\pi r^{2}(6)

or

V=6 \pi r^{2}

We can now take the derivative to this formula so we get:

\frac{dV}{dt}=2(6)\pi r \frac{dr}{dt}

Which simplifies to:

\frac{dV}{dt}=12\pi r \frac{dr}{dt}

We can now substitute the data provided by the problem to get:

\frac{dV}{dt}=12\pi (1.9) (\frac{1}{3000})

which yields:

\frac{dV}{dt}=0.0239\frac{in^{3}}{min}

3 0
3 years ago
What is the VALUE OF X PLS HELPP
baherus [9]

Answer: I think it would be 285.

Step-by-step explanation:

A circle is 360* so I did 360-75. Hope this helps!!!

4 0
3 years ago
PQ and QR are two sides of a regular 12-sided polygon. PR is the diagonal of the polygon.
skelet666 [1.2K]

The size of angle PRQ is 15°

Step-by-step explanation:

In any regular polygon of n-sided

  • All sides are equal in length
  • All angles are equal in measure
  • The measure of each interior angle is \frac{(n-2)*180}{n}
  • The measure of each exterior angle is \frac{360}{n}
  • The sum of the measures of the interior and exterior angle at the same vertex is 180°

∵ PQ and QR are two sides of a regular 12-sided polygon

∴ PQ = QR

∵ PR is a diagonal

∴ ∠PQR is an interior angle of the polygon

- By using the rule of the interior angle above

∵ n = 12

∴ m∠PQR = \frac{(12-2)*180}{12}

∴ m∠PQR = 150°

In Δ PQR

∵ PQ = QR ⇒ sides in a regular polygon

- Δ PQR is an isosceles Δ

∴ m∠PRQ = m∠RPQ ⇒ base angles of an isosceles Δ

The sum of the measures of the interior angles of a triangle is 180°

∵ m∠PQR + m∠PRQ + m∠RPQ = 180°

∴ 150 + m∠PRQ + m∠RPQ = 180°

- Subtract 150 from both sides

∴ m∠PRQ + m∠RPQ = 30

∵ m∠PRQ = m∠RPQ

- Divide their sum by 2 to find the measure of each one

∴ m∠PRQ = m∠RPQ = 30 ÷ 2 = 15°

∴ m∠PRQ = 15°

The size of angle PRQ is 15°

Learn more:

You can learn more about the triangles in brainly.com/question/3945600

#LearnwithBrainly

4 0
3 years ago
Evaluate each logarithm. 100 Points for all questions.
seraphim [82]

Basic properties that will be used:

\log_ab^n=n\log_ab

x^{1/n}=\sqrt[n]x

\log_aa=1

All of these expression can be written to match on or more of the patterns above.

19.\quad\log_5\sqrt[4]{25}=\log_5(5^2)^{1/4}=\dfrac14\log_55^2=\dfrac12\log_55=\dfrac12

21.\quad9\ln e^3+4\ln e^5=27\ln e+20\ln e=27+20=47

23.\quad2\log_3\sqrt{27}=2\log_3(3^3)^{1/2}=\log_33^3=3\log_33=3

25.\quad4\log_2\sqrt8=4\log_2(2^3)^{1/2}=2\log_22^3=6\log_22=6

27.\quad\log_3\sqrt[6]{243}=\log_3(3^5)^{1/6}=\dfrac16\log_33^5=\dfrac56\log_33=\dfrac56

3 0
3 years ago
Read 2 more answers
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