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Fynjy0 [20]
4 years ago
9

Consider the half reaction below.

Chemistry
1 answer:
Arisa [49]4 years ago
6 0
Answer: <span>Chlorine is losing electrons and being oxidized.

Justification:

1) Chlorine is losing electrons

As you se the side of the products shwo two electrons, that means that those electons were lost by the reactants. Given that the only reactant is chlorine, it is releasing or losing those electrons.

2) Chlorine is being oxidized.

The substance that loses electrons and, hence, increases its oxidation number, is the substance being oxidized.

In this case Cl (-) in the side of the reactants has oxidation state (1-), while Cl2 in the side of the products has oxidation state 0. This shows that the oxidation state of chlorine increased, meaning that it is being oxidized.
</span>
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Which part of the mantle is still a solid but flows like a thick, heavy liquid?
marusya05 [52]

Hello!

Your answer is A, asthenosphere

<u>The asthenosphere is a part of the mantle</u>. It helps move the plates in the Earth.

It is <u>below the lithosphere,</u> between <u>80 and 200 km</u> below the surface.

Therfore, the asthenosphere is <u>the part of the mantle that is still a solid but flows like a thick, heavy liquid.</u>

<u />

Hope this helps!

Have a great day!

3 0
4 years ago
Read 2 more answers
Calculate ΔGrxn for this equation, rounding your answer to the nearest whole number. CaCO3(s) → CaO(s) + CO2(g) ΔGf,CaCO3 = −1,1
FrozenT [24]

Answer: \Delta G_{rxn} for the given reaction is 130.19kJ/mol

Explanation:

To Calculate the \Delta G_{rxn}, we use the formula:

\Delta G_{rxn}=\Delta G_{products}-\Delta G_{reactants}

For the given chemical reaction:

CaCO_3(s)\rightarrow CaO(s)+CO_2(g)

We are given:

\Delta G_{CaCO_3}=-1128.76kJ/mol\\\Delta G_{CaO}=-604.17kJ/mol\\\Delta G_{CO_2}=-394.4kJ/mol

Now, to calculate \Delta G_{rxn}, we put the values in the above equation:

\Delta G_{rxn}=(\Delta G_{CaO}+\Delta G_{CO_2})-\Delta G_{CaCO_3}

\Delta G_{reaction}=(-604.17-394.4)-(-1128.76)kJ/mol\\\Delta G_{reaction}=130.19kJ/mol

As, the value of \Delta G_{reaction} comes out to be positive, the reaction is said to be non-spontaneous reaction.

3 0
3 years ago
What's the possible contaminant in a solution of sodium sulfate and water with the answer being either sodium nitrate, calcium c
Tcecarenko [31]

Answer:

ansser a

Explanation:

lol jk u noob

5 0
3 years ago
Pentaborane-9,
frozen [14]

Given question is incomplete. The complete question is as follows.

Pentaborane (B_{5}H_{9}) is a colorless highly reactive liquid that will burst into flames when exposed to oxygen.the reaction is:

  2B_{5}H_{9}(l) + 12O_{2} \rightarrow 5B_{2}O_{2}(s) + 9H_{2}O(l)

Calculate the kilojoules of heat released per gram of the compound reacted with oxygen.the standard enthalpy of formation B_{5}H_{9}(l) , B_{2}O_{3}(s), and H_{2}O(l) are 73.2, -1271.94, and -285.83 kJ/mol, respectively.

Explanation:

As the given reaction is as follows.

   2B_{5}H_{9}(l) + 12O_{2} \rightarrow 5B_{2}O_{2}(s) + 9H_{2}O(l)

Therefore, formula to calculate the heat energy released is as follows.

       \Delta H = \sum H_{products} - \Delta H_{reactants}

Hence, putting the given values into the above formula is as follows.

         \Delta H = \sum H_{products} - \Delta H_{reactants}

     = 5 \times (-1271.94 kJ/mol) + 9 \times (-285.83 kJ/mol) - 2 \times (73.2 kJ/mol) - 12(0)

     = -9078.59 kJ/mol

Since, 2 moles of Pentaborane reacts with oxygen. Therefore, heat of reaction for 2 moles of Pentaborane is calculated as follows.

        \frac{\Delta H}{2 \times \text{molar mass of pentaborane}}      

         \frac{-9078.59 kJ/mol}{2 \times 63.12 g/mol}

                  = -71.915 kJ/g

Thus, we can conclude that heat released per gram of  the compound reacted with oxygen is 71.915 kJ/g.

8 0
3 years ago
Which of the following is true of the gas constant, R?
NikAS [45]

Answer: I think it’s A sorry if I’m wrong

Explanation:

6 0
3 years ago
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