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Ugo [173]
3 years ago
5

What is the approximate value of the length of the carbon-carbon bond in ethene?

Chemistry
1 answer:
MAVERICK [17]3 years ago
4 0

Answer:

The answer to your question is: 1.21 A°

Explanation:

Ethene has 1 double bond between its carbons and a single bonds between Carbon and Hydrogens

Structure of ethene

                                H₂C = CH₂

The length of single bonds is 1.42 A°                                    

The length of double bonds is 1.21 A°

The length of triple bonds is 1.10 A°

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If 18.7ml of 0.01500M aqueous HCl is required to titrâtes 15.00ml of an aqueous solution of NaOH to the equivalence point, what
sweet [91]

Answer:

0.0187 M

Explanation:

Step 1: Write the balanced neutralization reaction

NaOH + HCl ⇒ NaCl + H₂O

Step 2: Calculate the reacting moles of HCl

18.7 mL of 0.01500 M HCl react.

0.0187 L × 0.01500 mol/L = 2.81 × 10⁻⁴ mol

Step 3: Calculate the reacting moles of NaOH

The molar ratio of HCl to NaOH is 1:1. The reacting moles of NaOH are 1/1 × 2.81 × 10⁻⁴ mol = 2.81 × 10⁻⁴ mol.

Step 4: Calculate the molarity of NaOH

2.81 × 10⁻⁴ moles are in 15.00 mL of NaOH.

[NaOH] = 2.81 × 10⁻⁴ mol/0.01500 L = 0.0187 M

6 0
3 years ago
If you have 15g of sodium carbonate, what<br> mass of sodium is present in that sample?
Sati [7]

Answer: 6.75 g

Explanation:

5 0
3 years ago
For which of the following conversions does the value of the conversion factor depend upon the formula of the substance?
pochemuha

For which of the following conversions does the value of the conversion factor depend upon the formula of the substance?

The answer is C

3 0
3 years ago
Read 2 more answers
The Prandtl number, Npr, is a dimensionless group important in heat transfer calculations. It defined as Cuk, where C, is the he
VARVARA [1.3K]

Answer:

The Prandlt number for this fluid is 1630.

Explanation:

The Prandlt number is defined as:

Pr=\frac{C_p\mu}{k}

To compute the Prandlt number for this case, is best if we use the same units in every term of the formula.

\mu=1936\frac{lb}{ft*h}*\frac{1000g}{2.205lb}*\frac{3.281ft}{1m}*\frac{1h}{3600s}  \\ \\\mu=800 \frac{g}{m*s}

Now that we have coherent units, we can calculate Pr

Pr=\frac{C_p\mu}{k}=\frac{0.583*800}{0.286}= 1630

8 0
3 years ago
What mass of water must be used to make a 1.35 m solution that contains 8.20 mol NaOH?
Sergeeva-Olga [200]
Answer is: <span>mass of water is 6.07 kilograms.
</span>b(NaOH) = 1.35 m.
n(NaOH) = 8.20 mol.
b(NaOH) = n(NaOH) ÷ m(H₂O).
m(H₂O) = n(NaOH) ÷ b(NaOH).
m(H₂O) = 8.20 mol ÷ 1.35 mol/lg.
mm(H₂O) = 6.07 kg.
m - molality.
n - amount of substance.
6 0
3 years ago
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