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3 years ago

A student is trying to solve the set of two equations given below:

1 answer:

4 0

Multiply equation A by 2. x+z=6 If you replace the z with the 2, you can add whatever the amount x is to get 6!

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Which arrangement from these fractions is from least to greatest?

iragen [17]

from least to greatest

D.) 3/5, 2/3, 5/7

7 0

3 years ago

Some people advise that in very cold weather, you should keep the gas tank in your car more than half full. Irene's car had 5.

Alex787 [66]

Answer:

$27,72

Step-by-step explanation:

The information that we have its

The cost gas its $3.60 per gallon
Irene's car had 5.3 gallons
Irene's car tank is 13 gallons

so now for the know, How much did Irene spend on gas?

First

The gas that its necesary for filled de tank its

13gallons-5,3gallons=7,7 gallons

The cost for 7,7 its

7,7g*3,6$/g= $27,72

7 0

3 years ago

A food-packaging apparatus underfills 10% of the containers. Find the probability that for any particular 10 containers the numb

Maksim231197 [3]

Answer:

a) $P(X = 1) = 0.38742$

b) $P(X = 3) = 0.05740$

c) $P(X = 9) = 0.00000$

d) $P(X \geq 5) = 0.00163$

Step-by-step explanation:

For each container, there are only two possible outcomes. Either it is undefilled, or it is not. This means that we can solve this problem using the binomial probability distribution.

Binomial probability distribution:

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem

There are 10 containers, so $n = 10$ .

A food-packaging apparatus underfills 10% of the containers, so $p = 0.1$ .

a) This is P(X = 1)

$P(X = 1) = C_{10,1}.(0.1)^{1}.(0.9)^{9} = 0.38742$

b) This is P(X = 3)

$P(X = 3) = C_{10,3}.(0.1)^{3}.(0.9)^{7} = 0.05740$

c) This is P(X = 9)

$P(X = 9) = C_{10,9}.(0.1)^{9}.(0.9)^{1} = 0.00000$

d) This is $P(X \geq 5)$ .

Either the number is lesser than five, or it is five or larger. The sum of the probabilities of each event is decimal 1. So:

$P(X < 5) + P(X \geq 5) = 1$

$P(X \geq 5) = 1 - P(X < 5)$

In which

$P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{10,0}.(0.1)^{0}.(0.9)^{10} = 0.34868$

$P(X = 1) = C_{10,1}.(0.1)^{1}.(0.9)^{9} = 0.38742$

$P(X = 2) = C_{10,2}.(0.1)^{2}.(0.9)^{8} = 0.1937$

$P(X = 3) = C_{10,3}.(0.1)^{3}.(0.9)^{7} = 0.05740$

$P(X = 4) = C_{10,4}.(0.1)^{1}.(0.9)^{9} = 0.38742$

$P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.34868 + 0.38742 + 0.19371 + 0.05740 + 0.01116 = 0.99837$

Finally

$P(X \geq 5) = 1 - P(X < 5) = 1 - 0.99837 = 0.00163$

3 0

3 years ago

Please answer a and b

Assoli18 [71]

Answer:

(-2,1) (-1,1),(0,1)

Step-by-step explanation:

find the gradient first

6 0

3 years ago

Bag A contains 3 red balls and 3 blue balls.

dezoksy [38]

Answer:

30% probability that the ball taken from B is red.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

In this question:

Red ball from urn A:

3/6 = 1/2 probability of getting a red ball from urn A.

Then urn B will have 5 balls, 2 of which are red, so 2/5 probability of getting a red ball.

Blue ball from urn A:

3/6 = 1/2 probability of getting a blue ball from urn A.

Then urn B will have 5 balls, 1 of which is red, so 1/5 probability of getting a red ball.

Total:

$p = \frac{1}{2}*\frac{2}{5} + \frac{1}{2}*\frac{1}{5} = \frac{2}{10} + \frac{1}{10} = \frac{3}{10}$

3/10 = 0.3 = 30%.

30% probability that the ball taken from B is red.

4 0

3 years ago