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nevsk [136]
2 years ago
8

Question 16 of 98

Mathematics
2 answers:
riadik2000 [5.3K]2 years ago
6 0
The answer would be b
charle [14.2K]2 years ago
6 0

Answer:

C

Step-by-step explanation:

C. Since .12333 has a repeating character and .115 has a definitive end, they are both rational

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Which expression is equal to x + (y + z)?
arsen [322]
X+(y+z) is equal to saying (x+y)+z

This is called the cumulative property when order doesn’t matter or doesn’t change the equation. As in 1+2 is the same as 2+1. No matter which way we get the same answer. This only works with multiplication and addition though. Hope this helps. Any questions please just ask!! Thank you so much!!
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3 years ago
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HELP PLSSSS ILL GIVE U 22 PLSSS HELPO
dangina [55]

Answer: no they are not

Step-by-step explanation:

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Calculate the average rate of change over the intervals [0, 20] and [60, 80]. What does the average rate on these intervals tell
Assoli18 [71]

\frac{20 - 80}{0 - 60 }  = slope \: or the \: rate \: of \: \\  change \:  \\  \\      \frac{ - 60}{ - 60}  = 1
It tells you that over these intervals the balloon is going at a constant speed.
4 0
3 years ago
What did they do incorrectly <br>40 + 70 + ? = 360<br> 110 + ? = 360<br> -110 -110 <br>? = 250
Arte-miy333 [17]

Answer:

I guess they subtracted a 110 from -110 instead of subtracting from 360

6 0
3 years ago
Element X is a radioactive isotope such that its mass decreases by 59% every day. If an experiment starts out with 390 grams of
miss Akunina [59]

Answer:

The function that represents the mass of the sample after t days is A(t) = 390(0.41)^t.

The percentage rate of change per hour is of -2.46%.

Step-by-step explanation:

Exponential amount of decay:

The exponential amount of decay for an amount of a substance after t days is given by:

A(t) = A(0)(1-r)^t

In which A(0) is the initial amount, and r is the decay rate, as a decimal.

Element X is a radioactive isotope such that its mass decreases by 59% every day. The experiments starts out with 390 grams of Element X.

This means, respectively, that r = 0.59, A(0) = 390

So

A(t) = A(0)(1-r)^t

A(t) = 390(1-0.59)^t

A(t) = 390(0.41)^t

The function that represents the mass of the sample after t days is A(t) = 390(0.41)^t.

Hourly rate of change:

Decreases by 59% every day, which means that for 24 hours, the rate of change is of -59%. So

-59%/24 = -2.46%

The percentage rate of change per hour is of -2.46%.

5 0
3 years ago
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