The relative frequencies for the given table are:
- Male → 13/44
- Female → 17/86
- Adult → 29/86
- Baby → 7/43
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How to get the relative frequencies?</h3>
The relative frequency of a given element out of a set, is given by the quotient between the number of that element and the total number of the set.
Here we can see that the total number of moose is:
52 + 34 + 58 + 28 = 172
There are 52 male moose, then the relative frequency for male moose is:
M = 52/172 = 26/86 = 13/44
There are 34 female moose, then the relative frequency is:
F = 34/172 = 17/86
There are 58 adult moose, so the relative frequency is:
A = 58/172 = 29/86
There are 28 baby moose, so the relative frequency is:
B = 28/172 = 14/86 = 7/43
If you want to learn more about relative frequency:
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Answer:
The ratio of the difference of the two means to Sidney's mean absolute deviation =
= 1.2195
Step-by-step explanation:
P.S - The exact question is -
Given - The means and mean absolute deviations of Sidney’s and Phil’s grades are shown in the table below.
Sidney’s Grades Phil’s Grades
Mean 82 78
Mean Absolute Deviation 3.28 3.96
To find - Which expression represents the ratio of the difference of the two means to Sidney’s mean absolute deviation?
Proof -
Given that Mean of Sidney Grades = 82
Mean of Phil's Grades = 78
So,
The difference of two means = 82 - 78 = 4
Also,
Given, Mean Absolute Deviation of Sydney = 3.28
Now,
The ratio of the difference of the two means to Sidney's mean absolute deviation =
= 1.2195
16 wide
Step-by-step explanation:
because i do 8 x 2
A function has a vertical asymptote where it is not defined, and the logarithm is defined only if its argument is strictly positive: it has a vertical asymptote if its argument is zero, and is not defined if its argument is negative.
So, you have a vertical asymptote where

The answer is 50, just divide 10 and 2, you get 5 and multiply the 5 with the 10